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Readme [11.4K]
3 years ago
7

I need help and ty for helping

Mathematics
1 answer:
Ksivusya [100]3 years ago
5 0
She can make 8

48/6=8
32/4=8
You might be interested in
Simplify the equation 32^3/5
scoundrel [369]
Ok so to simplify 32^3/5, you will need to know the steps, so I'll tell u the step by step solution. ;D

So Step 1: You have to <span>Raise 32 to the 3rd power:

</span><span><span>1.1 </span>    32 = 2</span>⁵
(32)³ = (2⁵)³ = 2¹⁵

<span>the equation has ended on step 1, so now is:

</span><span>  2</span>¹⁵
<span>------
  5
</span>
Now step 2:
Simplify it 

(you can't simplify this equation but these is the steps you gotta do on other equations so I'm just giving an example.)

  2¹⁵
------
  5

So basically your final result is:

  2¹⁵
------
  5

=====End=====

Hope you understand it :D

-Skylor/Crystal
6 0
3 years ago
A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she
marta [7]

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

​How much water, in milliliters, does the student have left in the bottle?

Answer:

the amount of water the student have left in the bottle is 250 milliliters

Step-by-step explanation:

A student had 500 milliliters of water in a water bottle. She drank 25% of the water before soccer practice. After practice, she drank 1/3 of the remaining water.

​How much water, in milliliters, does the student have left in the bottle?

Before the soccer practice, she drank 25 % of the water

25% of the water = 25% of 500

                             = 25% × 500

                              =\frac{25}{100} ×  500

At the right hand-side of the equation, the two zeros will cancel-out the other two zeros, hence;

                                = 25 × 5

                                 =125

25% of the water = 125 milliliters

From the question, it was said that drank 25% of the water before soccer, this implies that she drank 125 milliliters from the water bottles.

If she drank 125 milliliters of  from a 500 milliliters water contain in the water bottle, then the amount of water left will be 500 ml - 125 ml = 375 ml

This implies that before the soccer practice she had 375 milliliters of water left in the water bottle.

After the practice, she drank 1/3 of the remaining water, which means after the practice she drank 1/3 of 375

1/3 of 375 = \frac{1}{3} × 375 = \frac{375}{3} = 125

After the practice she drank 125 milliliters of water from her 375 milliliters water.

The amount of water she have left after the practice will be;

375 milliliters - 125 milliliters = 250 milliliters

Therefore, the amount of water the student have left in the bottle is 250 milliliters

8 0
3 years ago
Answer the question below
Kobotan [32]

Answer:There are 96 apples in the 12th bag.

Step-by-step explanation:

Firstly, you add the number of apples in the 11 bags.

6+28+16+27+10=87

If the mean number of apples in the 12 bags were 8, the total number of apples are 96.  

Using this info, we subtract 87 from 96 to 9.

Hence, there are 9 apples in the 12th bag.

8 0
4 years ago
a ratio of science books to art books is 2:5. 20 % of the books were unsold and 2240 were sold. total amount of each book?
mash [69]
Science = 512
art = 1,280
7 0
3 years ago
Element X decays radioactively with a half life of 14 minutes. If there are 760 grams of Element X, how long, to the nearest ten
Mkey [24]

Answer:

85.5 minutes

Step-by-step explanation:

The amount of an element that will remain after time t can be expressed as a function of initial amount N0, time t, and half life th as;

Nt = N0 × e^(-λt)

Where;

Decay constant λ = ln(2)/th, substituting into the equation;

Nt = N0 × e^(-ln(2)t/th)

We need to make t the subject of formula;

Nt/N0 = e^(-ln(2)t/th)

ln(Nt/N0) = -ln(2)t/th

t = ln(Nt/N0) ÷ -ln(2)/th

Given;

Initial amount N0 = 760g

Final amount Nt = 11 g

Half life th = 14 minutes

the nearest tenth of a minute, would it take the element to decay to 11 grams can be derived using the formula;

t = ln(Nt/N0) ÷ -ln(2)/th

Substituting the given values;

t = ln(11/760) ÷ -ln(2)/14

t = 85.5 minutes

4 0
3 years ago
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