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mestny [16]
2 years ago
5

Please Help me. Also if you could show your work thatd be great.

Mathematics
1 answer:
Over [174]2 years ago
5 0

Answer:

3) all \: real \: numbers, (  - \infty , \infty ), or -  \infty  \leqslant x \leqslant  \infty (same thing)

4) -  \infty  < y < 0 or ( -  \infty ,0) (same thing)

5) -2 or (0, -2) (same thing)

Step-by-step explanation:

3) Domain represents the amount of x-values in a function. The image shows that the function's arrows point in both directions (right and left), infinitely, so the domain would be all \: real \: numbers, (  - \infty , \infty ), or -  \infty  \leqslant x \leqslant  \infty(same thing).

4) Range represents the amount of y-values in a function. The function goes downward forever (- \infty  < y) by the indication of an arrow and halts just under the y-axis (y < 0). After combining these two inequalities, you see that the range is -  \infty  < y < 0 or ( -  \infty ,0) (same thing).

5) The y-intercept is where the function crosses the y-axis. In this function, the y-intercept is -2 or (0, -2) (same thing).

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How much would you need to deposit in an account now in order to have $6000 in the account in 5 years
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5 0
3 years ago
(12x5+3x25)-8<br><br> 12x5=60<br> 3x25=75<br> 60+75=135<br> 135-8=127
lions [1.4K]

Answer:

127

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The table shows values for functions f(x) and g(x). x f(x)=2x−3 g(x)=73x−2 −1 −52 −133 0 −2 −2 1 −1 13 2 1 83 3 5 5 4 13 223 5 2
Verizon [17]

0 and 2

f(x) = g(x) will be the input or x value at which f and g have the same output or y value. Look in the table where two numbers repeat right next to each other.

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6 0
3 years ago
Which function will have a y-intercept at –1 and an amplitude of 2?
Angelina_Jolie [31]

Answer:

Options B and D.

Step-by-step explanation:

The general form of sine function

h(x)=A\sin (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

The general form of cosine function

h(x)=A\cos (Bx+C)+D

where, |A| is amplitude, \frac{2\pi}{B} is period, \frac{-C}{B} is phase shift and D is y-intercept.

In function, f(x)=-\sin x-1

Amplitude : |A|=1

y-intercept : -1

In function, f(x)=-2\sin x-1

Amplitude : |A|=2

y-intercept : -1

In function, f(x)=-\cos x

Amplitude : |A|=1

y-intercept : 0

In function, f(x)=-2\cos x-1

Amplitude : |A|=2

y-intercept : -1

Therefore, the correct options are B and D.

4 0
3 years ago
Read 2 more answers
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