By applying algebraic handling and the concept of polynomials, we conclude that the <em>quadratic</em> equation 6 · x² + 18 · x = 0 has two roots: 0, - 3.
<h3>How to solve a quadratic equation</h3>
In this question we must apply <em>algebraic</em> rules to find the roots of a <em>quadratic</em> equation, the roots are the values of the equation such that is equal to zero. Now we present the complete procedure:
6 · x² + 18 · x = 0
6 · x · (x + 3) = 0
x = 0 ∨ x = - 3
By applying algebraic handling and the concept of polynomials, we conclude that the <em>quadratic</em> equation 6 · x² + 18 · x = 0 has two roots: 0, - 3.
To learn more on quadratic equations: brainly.com/question/17177510
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Answer:
0.0824 (may be incorrect)
1/x+2-1/2=2-x-2/2(x+2)=-x/2x+4
(-x/2x+4)/x=(-x/2x+4)*(1/x)=-1/2x+4
lim x--->0 (-1/2x+4)=-1/4
For second one the answer is 14
Answer:
4(1 - 4x + 7y)
Step-by-step explanation:
The only factor common to all three terms is 4.
Factoring out the 4, we get 4(1 - 4x + 7y)