PLEASE HELP!!!! Complete the proof for the following conjecture. WILL GIVE BRAINLIEST!

Flura [38]

9 and 1/2 is the answer. We can find this by simply subtract 1 1/2 from 12.

7 0

3 years ago

Use the formula for the area of a rectangle, A = lw, where A represents the area, l represents the length, and w represents the

IgorLugansk [536]

Answer:

Area = length × breadths

5 0

3 years ago

Solve for x.<br> x^2 + 6 = 10

Ostrovityanka [42]

Steps To Solve:

x² + 6 = 10

~Subtract 6 to both sides

x² + 6 - 6 = 10 - 6

~Simplify

x² = 4

~Take square root of 4

x² = ±√4

~Simplify

x = -2 or x = 2

Best of Luck!

5 0

3 years ago

Charlie watched 1 3 of a movie in the morning, and he watched some more at night. By the end of the day, he still had 2 5 of the

Finger [1]

Answer: 4/15 of the movie

Step-by-step explanation:

In the morning, Charlie watched ¹/₃ of a movie. He then watched some more at night.

At the end of the day, he still had ²/₅ of the movie to watch.

The proportions of an item must always add up to one. This means that if you added the 1/3 to the 2/5 and then to the fraction Charlie watch at night, they should add up to one.

¹/₃ + ²/₅ + x = 1

x = 1 - ¹/₃ - ²/₅

$x = \frac{15 - 5 - 6 }{15} \\\\x = \frac{4}{15}$

3 0

3 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

3 years ago