95% of red lights last between 2.5 and 3.5 minutes.
<u>Step-by-step explanation:</u>
In this case,
- The mean M is 3 and
- The standard deviation SD is given as 0.25
Assume the bell shaped graph of normal distribution,
The center of the graph is mean which is 3 minutes.
We move one space to the right side of mean ⇒ M + SD
⇒ 3+0.25 = 3.25 minutes.
Again we move one more space to the right of mean ⇒ M + 2SD
⇒ 3 + (0.25×2) = 3.5 minutes.
Similarly,
Move one space to the left side of mean ⇒ M - SD
⇒ 3-0.25 = 2.75 minutes.
Again we move one more space to the left of mean ⇒ M - 2SD
⇒ 3 - (0.25×2) =2.5 minutes.
The questions asks to approximately what percent of red lights last between 2.5 and 3.5 minutes.
Notice 2.5 and 3.5 fall within 2 standard deviations, and that 95% of the data is within 2 standard deviations. (Refer to bell-shaped graph)
Therefore, the percent of red lights that last between 2.5 and 3.5 minutes is 95%
X^2 + 10X + 21
(X + 3)(X + 7)
The probability that both marbles will be a red color is:
6..... ⇔ number that satisfies the constraint
_____
15..... ⇔ number of outcomes
Answer:
x *2 + (28-x)*4 = 100
Step-by-step explanation:
Given
Total number of questions in the paper = 28
Out of these 28 questions let us say that x number of questions are of 2 points and 28-x questions are of 4 points.
Also, the complete test is of 100 marks
Thus, the linear equation representing the
x *2 + (28-x)*4 = 100
