ABC is a equilateral triangle .
Proof :-
Let's assume both circles as C1 and C2 [ as shown in the figure ]
- AB is the radius of circle C1
- AB is the radius of Circle C2
AC is the radius of circle C1.
BC is the radius of circle C2 .
AB and AC both are radius of circle C1 so both are equal ie AB = AC .
AB and BC both are radius of circle C 2 so both are equal ie AB = BC .
Hence we conclude that .
AB = BC = AC.
So the triangle is equilateral triangle.
Answer:
See attachment
Step-by-step explanation:
The given system is :
Let us equate both equations and solve for x.
The the two lines of this system will meet at (-4,9)
The graph is shown in the attachment.
<h2>sorry I can't help you to solve the equation</h2>
<h3>
Answer: 5</h3>
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Work Shown:
x^2 - 5x + 1 = 0
x^2 + 1 - 5x = 0
x^2 + 1 = 5x
(x^2 + 1)/x = 5 .... where x is nonzero
(x^2)/x + (1/x) = 5
x + (1/x) = 5
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An alternative method involves solving the original equation using the quadratic formula. After you get the two roots x = p and x = q, you should be able to find that p + 1/p = 5 and also q + 1/q = 5 as well.
In this case,
p = (5 + sqrt(21))/2
q = (5 - sqrt(21))/2
I'm pretty sure the answer is "A matrix separates rational and irrational numbers." (Note: I'm not that great with memorizing definitions, but I'm pretty sure.) Hope this helps :)
