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Papessa [141]
3 years ago
10

Name each angle four ways.​

Mathematics
1 answer:
Nata [24]3 years ago
4 0

Answer:

right angled triangles

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a (1,4) b (-1,2) c (5,-2) are the vertices of triangle abc find the sum of coordinates of the point where the right bisector of
zmey [24]

Answer:

3.

Step-by-step explanation:

Find the midpoint of BC:

midpoint = (-1+5)/2, (2-2)/2 = (2, 0).

The slope of BC = (2 - -2) / (-1-5) = -2/3.

Find the equation of the right bisector of BC:

The slope = -1 / -2/3 = 3/2.

y-y1 = m(x-x1)

y - 0 = 3/2(x - 2)

y = 3/2x - 3.

Now find the equation of the median through C:

The midpoint of AB = (1 - 1)/2, (4+2)/2

= (0, 3).

The equation of the median:

The slope = (-2-3) / (5-0)

= -1.

The equation is:

y - 3 = -1(x - 0)

y -3 = -x.

Now we find the point of intersection by solving the 2 equations:

y - 3 = -x

y = 3/2x - 3

y = -x + 3

So:

3/2x - 3 = -x + 3

3/2x + x = 6

5/2 x = 6

x = 12/5.

y =  -12/5 + 3

= -12/5 + 15/5

= 3/5.

The sum of the coordinates = 12/5 + 3 /5

= 15/5

= 3.

3 0
3 years ago
What is 7a to the power of 2 - 2a to the power of 2
harkovskaia [24]

Answer:

5a to the power of 2 ofc

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Lan parents asked him to create a budget For his 1000 monthly income he determines That he would like to save the remaining amou
LiRa [457]

Answer:

for an equal income to everyone you can do 250 to each person adding up to 750 then 250 to save

Step-by-step explanation:

6 0
3 years ago
−11b+7=40<br> Like what am I supposed to do??
Nataly [62]

Answer:

The answer is 3

Step-by-step explanation:

First write the equation as you see it.

-11b+7=40

Then switch the take away seven from the left side then place it in the right side but as a minus.

-11b=40-7

Next do the math on the right side.

-11b=33

Once you have done that you divide the number on right with the number on the left which leaves you with the answer.

b=-3

Hope this helped :)

8 0
3 years ago
What is the expected number of times that i draw a green m&amp;m?
Shalnov [3]
Can you please elaborate on your question
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3 years ago
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