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Luda [366]
3 years ago
15

Please Help. If m ∠ EJF=56, find m ∠ FHK.

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

Answer: 124 degrees

========================================================

Explanation:

If we assume these two things:

  • JC parallel to KD
  • JA parallel to HB

Then this would allow us to say that angle EJF = angle FHG because they are corresponding angles.

So that means angle FHG = 56

This then leads to:

angle FHK = 180 - (angle FHG) = 180 - 56 = 124 degrees

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Answer:

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Step-by-step explanation:

a

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3 years ago
The function f(x)= 1 divided by x is an example of an exponential function.<br> true<br> false
tensa zangetsu [6.8K]

This is a false statement.

Exponential functions are when there is a variable in the exponent. With x being in the denominator, this is the same as the function x^-1. Since the exponent is a number and not a variable, it is not a exponential function.

5 0
4 years ago
Provide me three coordinate points for the following, given the Slope and Y-intercept. 5. Slope = 7/9, Y intercept = 12(give me
madam [21]

Since we have that the slope is m = 7/9 and the y-intercept is b = 12, we can write the equation of the line in slope-intercept form:

\begin{gathered} y=mx+b \\ \Rightarrow y=\frac{7}{9}x+12 \end{gathered}

to find three coordinate points, we can use arbitrary values on x to get the y-coordinate. To make things easier, let's use x = 9, 18 and 27:

\begin{gathered} x=9 \\ \Rightarrow y=\frac{7}{9}(9)+12=7+12=19 \\ x=18 \\ \Rightarrow y=\frac{7}{9}(18)+12=7(2)+12=14+12=26 \\ x=27 \\ \Rightarrow y=\frac{7}{9}(27)+12=7(3)+12=21+12=33 \end{gathered}

therefore, the line with slope m = 7/9 and y-intercept 12 passes through the three points (9,19), (18,26) and (27,33)

8 0
1 year ago
5.
Delicious77 [7]

You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:

<em>a(t)</em> = 40 ft/s²

<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>

<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>

<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>

<em />

<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>

<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>

<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²

<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²

6 0
3 years ago
-50 POINTS- please help
e-lub [12.9K]

Answer:

-13

-10

Step-by-step explanation:

A x = B

To find X

A ^ -1 A  x = A ^ -1 B

x = A^ -1 B

x = -3/2  -5/2      2

     -1       -2         4

Across times down

-3/2 * 2 + -5/2 *4 = -13

-1 *2 -2 * 4 = -10

The matrix is

-13

-10

7 0
4 years ago
Read 2 more answers
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