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denis-greek [22]
3 years ago
5

PLSSSSS HELPP MEEEEEEEEE PLS RESPOND TO ME

Mathematics
1 answer:
aivan3 [116]3 years ago
8 0

Answer:

HOLAAAAAO

Step-by-step explanation:

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I WOULD LOVE IF SOMEONE CAN ANSWER THIS QUESTION FOR ME!
postnew [5]

Answer:

32 cm^3

Step-by-step explanation:

The cube is 4 across by 4 high by 2 wide

4*4*2 = 32 cm^3

7 0
3 years ago
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Please help me with this <br><br><br> also good morning!
Doss [256]

Answer:

Divide both sides by 6 :)

8 0
2 years ago
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1. What is the slope of the line that passes through the given points? <br> (2, 12) and (6, 11)
Y_Kistochka [10]

Answer:

-1/4x

Step-by-step explanation:

11-12/6-2 = -1/4

8 0
3 years ago
Helpppppppppppppppppp
Brilliant_brown [7]

Answer:

<em>Option A; the tournament did begin with 128 teams</em>

Step-by-step explanation:

We can see that this equation is represented by compound interest, in other words an exponential function, either being exponential growth or exponential decay;

f ( x ) = a + ( b )^x, where a ⇒ start value, b ⇒ constant, x ⇒ ( almost always considered ) time, but in this case rounds

Option A; The equation is given to be t ( x ) = 128 * ( 1/2 )^x. Given by the above, 128 should represent the start value, hinting that the tournament <em>did indeed begin with 128 teams</em>

Option B; As the rounds increase the number of teams approach 128. Now mind you 128 is the start value, not the end value, which would mean that <em>this statement is false</em>

Option C; The tournament began with 1/2 teams. Theoretically that would not be possible, but besides that the tournament began with 128 teams, only differed by 1/2 times as much every round. <em>This statement is thus false</em>

Option D; This situation actually represents exponential decay. If each round the number of teams differed by 1/2 times as much, the number of teams remaining is less than before, and thus this models exponential decay, not growth<em> ( statement is false )</em>

<em>Answer : Option A; the tournament did begin with 128 teams</em>

4 0
3 years ago
Used to find the midpoint between two points (x1,y1) and (x2,y2)
9966 [12]

Answer:

The midpoint is

( (x1+x2)/2, (y1+y2)/2)

Step-by-step explanation:

To find the x coordinate of the midpoint

(x1+x2)/2

To find the x coordinate of the midpoint

(y1+y2)/2

The midpoint is

( (x1+x2)/2, (y1+y2)/2)

7 0
2 years ago
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