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Natasha_Volkova [10]
2 years ago
6

Hellooooooooo im just bored and just to get yall some pointss whats : 3x4= ?

Mathematics
2 answers:
andrew-mc [135]2 years ago
4 0

Answer:

thank youuuuuuuu<uuu thank you

tamaranim1 [39]2 years ago
4 0

Answer:

3×4=12

I hope this helps and thanks for the points

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Name the line of reflection used to map each preimage to its image
rewona [7]

Answer:

From the picture attached,

9). When pre-image KLMN is a reflected across x = -2, we get image K'L'M'N'.

   Therefore, line of reflection will be x = -2

10). In this picture line of reflection which passes through origin (0, 0) and slope = 1 will be,

y = x.

11). Since, all the points of image and preimage points are equidistant from x-axis, line of reflection will be x-axis or y = 0.

12). Line passing through midpoint of the line joining BB' will be the line of reflection.

Coordinates of B → (5, 3)

Coordinates of B' → (5, 7)

Coordinates of BB' →  → (5, 5)

Therefore, line of reflection will be y = 5.

13). Coordinates of G → (2, 5)

    Coordinates of G' → (-2, 5)

    Midpoint joining the segment GG' →  → (0, 5)

    Therefore, line of reflection → x = 0

14). Line of reflection passing through (0, 0) and slope = -1

    y = -x

Step-by-step explanation:

3 0
2 years ago
Please help. Don’t understand this math problem!!!
anzhelika [568]

Answer:

the line will have a point at -5, as that is it's y- intercept, and the slope is one so each following point is one diagonal to it on the right side, as the slope is positive

Step-by-step explanation:

3 0
3 years ago
Mary wants to hang a mirror in her room. The mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and
Umnica [9.8K]

Answer:

The quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

Step-by-step explanation:

Refer to the attachment for the diagram.

Consider EFGH as the the frame and ABCD as the mirror which is to be hanged.

Let me the "x" be the thickness of the frame as shown in diagram.

Given that, BC = 3 ft and DC = 2 ft which is the dimensions of the mirror.

Now to calculate the length and width of the frame consider following calculation,

Width of frame HG = x + DC + x  

Width of frame HG = x + 2 + x  

Width of frame HG =  2 + 2x  

2x is the addition of the thickness which is present on both side of mirror

Length of frame FG = x + BC + x

Length of frame FG = x + 3 + x

Length of frame FG = 3 + 2x

Since it is an rectangular frame, so using the formula for area of rectangle

Area\:of\:rectangle = length \times width

Given that area of frame is 7\:ft^{2}

Substituting the value,

7 = \left(3+2x\right)\times \left(2+2x\right)

Therefore, the quadratic equation used to determine the thickness of frame is \left(3+2x\right)\times \left(2+2x\right)=7

8 0
2 years ago
Describe the graph of a quadratic function
maw [93]
So, given a quadratic function, y = ax2<span> + bx + c, when "a" is positive, the </span>parabola<span> opens upward and the vertex is the </span>minimum<span> value. On the other hand, if "a" is negative, the graph opens </span>downward<span> and the vertex is the </span>maximum<span> value. To put it in complicated terms. Or when A is positive the graph is shaped like a U but if A is negative the graph is an upside down U


</span>
7 0
2 years ago
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Use the relationships between the angles to solve for x <br><br> x = _____ degrees
Svetllana [295]

Answer:

x = 100

Step-by-step explanation:

3 0
3 years ago
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