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Svetlanka [38]
3 years ago
5

DO,K = (5, 0) (10, 0) The scale factor is 1/2 2 5

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0
If the preimage point is (5,0) and the image point is (10,0)
then the scale factor is k = 2

Basically the coordinates of the old point have doubled (multiplied by 2)

x = 5 is the old x coordinate
x = 10 is the new x coordinate (5*2 = 10)

y = 0 is the old y coordinate
y = 0 is the new y coordinate (0*2 = 0, no change)
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HELP ASAP
Westkost [7]

Answer:

(5 1/2)(7.25)=

11/2(7.25)

=39.875

=39.875

Step-by-step explanation:

multiply 5 1/2 by 7.25 and u will have yo answer

5 0
3 years ago
Read 2 more answers
What is the percent of change from 500,000 to 400,000?
antoniya [11.8K]

Answer:

20%

Step-by-step explanation:

8 0
2 years ago
The scale factor for the lengths of two similar solids is 3/1.
Maslowich

Answer:

A

Step-by-step explanation:

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3 years ago
What is the determinant of the coefficient matrix of this system? <br> 4x-3y=-8 <br> 8x-3y=12
gladu [14]

The coefficient matrix is build with its rows representing each equation, and its columns representing each variable.

So, you may write the matrix as

\left[\begin{array}{cc}\text{x-coefficient, 1st equation}&\text{y-coefficient, 1st equation}\\\text{x-coefficient, 2nd equation}&\text{y-coefficient, 2nd equation} \end{array}\right]

which means

\left[\begin{array}{cc}4&-3\\8&-3\end{array}\right]

The determinant is computed subtracting diagonals:

\left | \left[ \begin{array}{cc}a&b\\c&d\end{array}\right]\right | = ad-bc

So, we have

\left | \left[\begin{array}{cc}4&-3\\8&-3\end{array}\right] \right | = 4(-3) - 8(-3) = -4(-3) = 12

8 0
3 years ago
Suppose that the batting averages or AVG (hits per at-bat) of all players in the AAA baseball league are normally distributed wi
bulgar [2K]

Answer:

0.1

Step-by-step explanation:

Solving using empirical rule formula

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

Hence, the lower bound 95% =

μ - 2σ

Mean = 0.2

Standard deviation of 0.05

= μ - 2σ

= 0.2 - 2(0.05)

= 0.2 - 0.1

= 0.1

The lower bound is 0.1

6 0
3 years ago
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