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Pachacha [2.7K]
3 years ago
9

Can you guys help me find a flag that has at least one reflection and a translation in it? If not, then two flags that show thes

e transformations.
This is very urgent and I need to get it done soon, whoever is willing to help me I'll mark you as brainliest. Thank you!

Mathematics
1 answer:
Vladimir [108]3 years ago
4 0

Answer:

The united nations flag the translation can be any of the blue triangles and the reflection if the flag itself as it is symmetrical

Step-by-step explanation:

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Two people (A and B) travel from X and Y along different routes. their journeys each take the same amount of time. a’s route is
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Answer:

a’s average speed is 60km/h

Step-by-step explanation:

x = a’s average speed

60/40 = 90/x

Cross multiplication:

60x = 40x90

60x=3600

Divide both sides  by 60

x= 60

4 0
2 years ago
16 Use the Empirical Rule. (Do not use technology. Technology will give a slightly different answer.)
kotykmax [81]

Answer:

a)8.4kg to 10.6kg

b)7.3 kg to 11.7kg

c)16%

d) 95%

e) 0.15%

Step-by-step explanation:

The empirical rule formula states that:

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ

From the question,

Mean(μ) = 9.5 kg,

Standard Deviation (σ) = 1.1 kg.

a) 68% of the data is between which 2 values?

68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ .

μ - σ

= 9.5kg - 1.1kg

= 8.4kg

μ + σ

= 9.5kg + 1.1kg

= 10.6kg

Therefore, 68% of the data is between 8.4kg to 10.6kg

(b) 95% of the data is between which 2 values?

95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ .

μ - 2σ

9.5kg - 2(1.1)kg

9.5kg - 2.2 kg

= 7.3kg

μ + 2σ

9.5kg + 2(1.1)kg

9.5kg + 2.2 kg

= 11.7kg

Therefore, 95% of the data is between 7.3 kg to 11.7kg

(c) What percentage of the data is less than 8.4 kg?

We need to find how many standard deviations from the mean 8.4kg is, in order to know the percentage it falls under

μ - xσ = 8.4kg

= 9.5kg - 1.1x = 8.4kg

9.5 - 8.4 = 1.1x

1.1 = 1.1x

x = 1.1/1.1

x = 1

Hence, the percentage it falls under according to Empirical rule = 68%

The percentage of the data that is less than 8.4 kg is calculated as:

100 - 68/2 = 32/2 = 16%

(d) What percentage of the data is between 7.3 kg and 11.7 kg?

We have to find the Standard deviation that they fall under

For 7.3 kg

μ - xσ = 7.3kg

= 9.5kg - 1.1x = 7.3kg

9.5 - 7.3 = 1.1x

2.2 = 1.1x

x = 2.2/1.1

x = 2

μ + xσ = 11.7kg

= 9.5kg + 1.1x = 11.7kg

11.7 - 9.5 = 1.1x

2.2 = 1.1x

x = 2.2/1.1

x = 2

Therefore, based on the calculation above and the empirical formula rule, the percentage of the data is between 7.3 kg and 11.7 kg is 95%

(e) What percentage of the data is more than 12.8 kg?

μ + xσ = 12.8kg

9.5kg + 1.1x = 12.8kg

= 12.8- 9.5 = 1.1x

3.3 = 1.1x

3.3 = 1.1x

x = 3.3/1.1

x = 3

Hence, the percentage it falls under according to Empirical rule = 99.7%

The percentage of the data that is more than 12.8kg is calculated as:

100 - 99.7/2 = 0.3/2 = 0.15%

5 0
3 years ago
A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.
Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean(\mu) = 500 and a standard deviation(\sigma) =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = \dfrac{Y-\mu}{\sigma}

Z-score = \dfrac{625-500}{100}

⇒ Z-score = \dfrac{125}{100}

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