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soldi70 [24.7K]
3 years ago
7

What can you do if a decimal product has final zeros to the right of the decimal point

Mathematics
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

place the decimal point in the product so that the number of decimal places in product is the sum of decilal places in the factors. keep all zeros in the product when you place the decimal point. you can drop the zeros on the right once the decimal point has been placed in the product.

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Which expressions are equivalent ??<br>​
Basile [38]

Answer:

\huge\boxed{E.\ 5^{4+x}}

Step-by-step explanation:

Use:

a^n\cdot a^m=a^{n+m}

5^4\cdot5^x=5^{4+x}

5 0
2 years ago
Write an equation in slope intercept form for the line that passes through (-6,-2) and has a slope of 1/3
BabaBlast [244]

Answer:

y=1/3x-2

Step-by-step explanation:

Since the slope intercept form formula is y=mx+b all we need to do is input the values. So m is the slope. Input 1/3. X is next to it because we solve for this. B is the y intercept. Meaning its the point that crosses the line on the graph that is vertical. And you already have -2. Since we know: (x,y) so choose the y. And you have your equation.

Hope this helps!! If so please mark brainliest and rate/heart to help my account if it did!!

5 0
3 years ago
Three women and three children wish to cross a river in a canoe that will hold only one woman and or two children. they can all
zmey [24]
(w,k)
that is amount of women and children lefton original side


ok, first realize you must get children across first because who will row the boat back

first trip: 10min, 2 children across, (3,1)
2nd trip: 20min, 1 kid cross back (3,2)
3rd trip: 30min, 2 kids cross (3,0)
4th trip: 40 min, 1 kid cross baack (3,1)
5th trip: 50 min, 1 woman cross (2,1)
6th trip: 60 min, 1 kid cross back (2,2)
7th trip: 70 min, 1 woman cross (1,2)
8th trip: 80 min, 1 kid cross back (1,1)
9th trip: 90 min, 1 woman cross (0,1)
10th trip: 100min, 1 kid cross back (0,2)
11th trip: 110 min, 2 kids cross back (0,0)

min time is 110 mins or 1hr 50min
7 0
4 years ago
Going into a recent election, only about 62% of people old enough to vote were registered. In a community of about 55,200 eligib
luda_lava [24]
All we need to do is to divide the number of eligible voters by 62% to find out how many people have been registered:

55200 ÷ 62% =
= 55200 ÷ 62/100 =
= 55200 * 100/62 =
= 5520000 / 62 =
= 89032,25806451613 ≈          (note the rounding to the nearest whole number)
≈ 89032

Doublecheck:

89032 * 62% =
= 89032 * 62/100 =
= 5519984 / 100 =
= 55199,84 ≈                        (the difference is because of the rounding before)
≈ 55200

Answer: There were 89,032 people registered.
4 0
3 years ago
Constant of Variation
nadezda [96]

Answer:

D. G is closer to the axis, and f is closer to the y-axis.

Step-by-step explanation:

I calculated it logically

3 0
3 years ago
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