OMIGOSH!! I have this same book, ok I'm past this chapter so. Tell me the page and I'll refresh my memory to help.

$\implies 2^{2x}-2\cdot5^{2x}-(2^x)(5^x)>0$
let $2^x=a$ and $5^x=b$
So, $a^2-2b^2-ab>0$
divide by $b^2$, ($b^2>0$)
$\implies \left(\frac ab\right)^2-\left(\frac ab\right) -2>0$
this is a quadratic, in $\left(\frac ab\right)$, let it be $x$
So, $x^2-x-2>0$
Can you simplify it now?
57 that’s what g would equal
Answer: k= 10
Explanation:
? + 115= 180
180-115=65
the unknown interior angle is 65 degrees since they’re supplementary angles
every triangle has an interior angle total of 180 degrees. since we have the 65 degree angle known, the others can be solved.
180-65= 115
(4k+5)+(6k+10)= 115
10k+15= 115
-15 -15
10k= 100
k=10