Answer:

Step-by-step explanation:
Given
z = 119 + 120 i
Let 
Squaring both sides

Comparing real and imaginary part
Re(LHS)=Re(RHS)
...........................(1)
comparing Im(LHS)=Im(RHS)
120=2pq

Substitute q in 1


Let 



we take only Positive value because 
x=149.85

thus 

thus,


Step-by-step explanation:
We start by applying the Pythagorean theorem to the ladder, with its length L as the hypotenuse:

where x is the vertical distance from the top of the ladder to the ground and y is the horizontal distance from the bottom of the ladder to the wall. Taking the derivative of the above expression with respect to time, we get

Solving for dx/dt, we get

We know that

when x = 6 ft. So the rate at which the top of the ladder is going down is


The negative sign means that the distance x is decreasing as y is increasing.
Answer:
A difference of squares has the following form . Any two perfect squares connected by subtraction can be factored.
It factors to (a+b)(a-b).
Step-by-step explanation:
A binomial is an expression with only terms where at least one is a term with a variable. When we can factor for difference of squares, we can have two variable terms or just one with a constant.
A difference of squares has the following form . Any two perfect squares connected by subtraction can be factored.
It factors to (a+b)(a-b).
I believe it is d.
Equation is y= 1/2x.
When a number or fraction is next to a variable that means to multiply.
So let’s replace the variable,x, with 6.
If you multiply 1/2 by 6, you get 3.
If you multiply 1/2 by 24 you get 12.
Continue that process to find the other answers