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AveGali [126]
3 years ago
9

Im bad at math and i need help ;^;​

Mathematics
2 answers:
Anit [1.1K]3 years ago
7 0

Answer:

\sqrt{ {x}^{10} }  \div x \\  \frac{ \sqrt{ {x}^{9}x } }{x}  \\  =  \sqrt{ {x}^{9} }  \\  =  \sqrt{ {x}^{8}x }  \\  =  {x}^{4}  \sqrt{x}  \\ thank \: you

siniylev [52]3 years ago
4 0

Answer:

x⁴√x

Step-by-step explanation:

simplify x¹⁰ and x to √x⁹ then simplify the radical equation to x⁴√x

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What’s 20{5[100-3(25+35)+20]}
8_murik_8 [283]

Answer:

-6000

Step-by-step explanation:

20{5[100-3(25+35)+20]}            open the parenthesis

20{5[100-180+20]}         do the addition and subtraction in the square brackets

20{5[-60]}                        open the square brackets

20{-300}                           open curly brackets

-6000

6 0
3 years ago
Stages
solong [7]
Don't get the question wish i could help :(( sorry
6 0
3 years ago
Find the value of the derivative (if it exists) at the indicated extremum. (If an answer does not exist, enter DNE.)
Liono4ka [1.6K]

Answer:

The answer is "0".

Step-by-step explanation:

Please find the correct question in the attached file.

Given value:

\to f(x) =\frac{x^2}{x^2+5}\\\\

Formula:

\bold{\frac{d}{dx} \frac{u}{v} = \frac{ v \frac{du}{dx} - u \frac{dv}{dx}}{v^2}}

\to f'(x) =\frac{(x^2+5) 2x -2x^3 (2x)}{(x^2+5)^2}\\\\\to f'(0) =\frac{(0^2+5)2(0) -4(0)^4}{(0^2+5)^2}\\\\\to f'(0) =\frac{(0)(5) -2(0)}{(5)^2}\\\\\to f'(0) =\frac{0 - 0}{(5)^2}\\\\\to f'(0) =\frac{0}{25}\\\\\to f'(0) = 0

6 0
3 years ago
Did I do this right?
Dimas [21]
Yeah that’s correct
5 0
3 years ago
Read 2 more answers
The sum of two numbers is 82 and their difference is 26. find each of the numbers.
Zarrin [17]
54 because if x+y=82 and x-y=26 add 26 and 82 is 108 the divide it by 2 your answer is 54
7 0
3 years ago
Read 2 more answers
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