The volume of the solid of revolution is approximately 37439.394 cubic units.
<h3>
How to find the solid of revolution enclosed by two functions</h3>
Let be 
and 
, whose points of intersection are 
, 
, respectively. The formula for the solid of revolution generated about the y-axis is:
(1)
Now we proceed to solve the integral: 
(2)
![V = 6\pi \left[(y-1)\cdot \ln y\right]\right|_{1}^{e^{35/6}}](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Cleft%5B%28y-1%29%5Ccdot%20%5Cln%20y%5Cright%5D%5Cright%7C_%7B1%7D%5E%7Be%5E%7B35%2F6%7D%7D)
![V = 6\pi \cdot \left[(e^{35/6}-1)\cdot \left(\frac{35}{6} \right)-(1-1)\cdot 0\right]](https://tex.z-dn.net/?f=V%20%3D%206%5Cpi%20%5Ccdot%20%5Cleft%5B%28e%5E%7B35%2F6%7D-1%29%5Ccdot%20%5Cleft%28%5Cfrac%7B35%7D%7B6%7D%20%5Cright%29-%281-1%29%5Ccdot%200%5Cright%5D)
The volume of the solid of revolution is approximately 37439.394 cubic units. 
To learn more on solids of revolution, we kindly invite to check this verified question: brainly.com/question/338504
Given:
To find:
The missing value of m.
Solution:
We have,
Corresponding parts of similar triangles are proportional.
Putting the given values, we get
Multiply both sides by 10.
Therefore, the value of m is 5.
Answer: The area of the mirror is 113.14 sq. inches [approx.].
Step-by-step explanation: Given that a circular can till 375 ft² of land in 15 min.
We are to find the area of the mirror in square inches.
The AREA of a circle with radius 'r' units is given by
The diameter of the circular mirror is 12 inches, so the radius of the mirror will be
Therefore, the area of the circular mirror is
![A=\pi r^2=\frac{22}{7}\times 6^2=\dfrac{22\times 36}{7}=113.14~\textup{sq inches}~\textup{[approx.]}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D%5Cfrac%7B22%7D%7B7%7D%5Ctimes%206%5E2%3D%5Cdfrac%7B22%5Ctimes%2036%7D%7B7%7D%3D113.14~%5Ctextup%7Bsq%20inches%7D~%5Ctextup%7B%5Bapprox.%5D%7D)
Thus, the area of the mirror is 113.14 sq. inches [approx.].
It means you multiply 6.2 x 0.48
which equals = 2.976
( ) mean multiply
