A bath tub drained at a constant rate. The table shows the number of gallons of water left in the tub after being drained for tw
1 answer:
The rate at which the water was drained from the tank is 6 gallons of water per minute (option A)
To know the speed at which the tank was drained, we must carry out the following operations:
Taking into account the information provided by the table we establish how much water has been drained from the tank in 20 minutes.
450 gallons - 330 gallons = 120 gallons.
Subsequently, we must divide the amount of water (120 gallons) that was drained by the time it was drained (20 minutes).
120 gallons ÷ 20 minutes = 6 gallons / minute.
According to the above, we can establish that the bath drain rate is 6 gallons / minute (option A).
Note: This question is incomplete because there is some missing information. Here is the complete information:
What is the rate at which the water was drained from the tank?
- 6 gallons of water per minute.
- 11 gallons of water per minute.
- 45 gallons of water per minute.
- 120 gallons of water per minute.
Learn more about linear equation in: brainly.com/question/11897796
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Answer:
8x - 5y = - 30
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Rearrange 8x - 5y = 2 into this form
Subtract 8x from both sides
- 5y = - 8x + 2 ( divide all terms by - 5 )
y = x -
← in slope- intercept form
with slope m =
• Parallel lines have equal slopes, hence
y = x + c ← is the partial equation of the parallel line
To find c substitute (- 5, - 2) into the partial equation
- 2 = - 8 + c ⇒ c = - 2 + 8 = 6
y = x + 6 ← in slope- intercept form
Multiply through by 5
5y = 8x + 30 ( subtract 5y from both sides )
0 = 8x - 5y + 30 ( subtract 30 from both sides )
8x - 5y = - 30 ← in standard form