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dolphi86 [110]
3 years ago
13

Let A={1,2,3,4,5,6,7,8}A={1,2,3,4,5,6,7,8}. Define a relation ∼∼ on AA by a∼ba∼b if and only if 33 divides a−ba−b for all a,b∈Aa

,b∈A.  1. Find all the pairs (a,b)∈A×A(a,b)∈A×A such that a∼ba∼b. 2. Show that ∼∼ is an equivalence relation on AA. 3.  Find the equivalence classes [2][2] and [3][3].​
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0

Define relation.

Let A and B are only two non-empty set,then A*B is cartesian product of A*B.Then any subset of A*B is known as the relation fromA to B.

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In triangleABC, angle B= 90 degrees, cos(C)=15/17 and AB = 16 what is the measure of Angle A, Angle C and angle AC
Sergeeva-Olga [200]

Answer:

m∠C=28°, m∠A=62°, AC=34.1 units

Step-by-step explanation:

Given In ΔABC, m∠B = 90°, , and AB = 16 units. we have to find m∠A, m∠C, and AC.

As,  cos(C)={15}/{17}

⇒ angle C=cos^{-1}(\frac{15}{17})=28.07^{\circ}\sim28^{\circ}

By angle sum property of triangle,

m∠A+m∠B+m∠C=180°

⇒ m∠A+90°+28°=180°

⇒ m∠A=62°

Now, we have to find the length of AC

sin 28^{\circ}=\frac{AB}{AC}

⇒ AC=\frac{16}{sin 28^{\circ}}=34.1units

The length of AC is 34.1 units

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Hi I would like to know how I can solve this problem.
murzikaleks [220]

The n-th term is

U_n = \dfrac14 n^2 (n+1)^2

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V_n = 8U_n = \boxed{2n^2(n+1)^2}

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