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3 years ago

What are some of the major issues with geotagging? What concerns you the most?

Computers and Technology

1 answer:

Finger [1]3 years ago

4 0

Answer:

Major issues with geotagging include the ability to pinpoint the exact location where a photo was taken, which raises privacy concerns.

What concerns me the most is when a geotag of an unsuspecting victim's location falls into the wrong hands.

Explanation:

Geotag - A geographical tag that can attach to SMS text messages, media such as photos and images, etc. The Geotag is measured in the longitude and latitude at which the image or text message took place.

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C++

Luden [163]

Answer:

The program to this question as follows:

Program:

//header file iostream

#include<iostream> //including file for use basic function

//using name space

using namespace std;

//main method

int main() //defining main method

{

int a[3][3]; //defining two dimension array

int x,y,sum=0; //defining variables

cout<<"Enter array elements: "<<endl; //message

for(x=0;x<3;x++) // for row

{

for(y=0;y<3;y++) //for column

{

cin>>a[x][y]; //input values from user.

}

//loop for calculting sum.

for(x=0;x<3;x++)

{

for(y=0;y<3;y++)

{

sum=sum+a[x][y];//add all elements

}

cout<<"Sum: "<<sum; //print sum.

return 0;

}

Output:

Enter array elements:

Sum: 45

Explanation:

In the above C++ programming language code first, a header file is included then the main method is declared, inside a main method 2D array that is "a[][]", and an integer variable is defined that are "i, j, and sum". In the next line for loop is used, this loop is used two times that can be described as follows:

The first time it is used for inserting elements from user ends.
The second time, it uses the sum variable to add all array elements. and in the last print function that is "cout" is used for print sum variable value.

7 0

3 years ago

Write a recursive function that calculates if two binary trees are similar?

ahrayia [7]

Answer:

bool identicaltrees(Node* root1,Node* root2)//function of type boolean true if idenctical false if not.

{

if(root1==NULL&&root2==NULL)//both trees are null means identical.

return true;

if(roo1 && root2)

{

if(root1->data==root2->data)//condition for recursive call..

{

return (identicaltrees(root1->left,root2->right)&&identicaltrees(root1->right&&root2->right);

}

else

return false;

}

Explanation:

In this function it of type boolean returns true if both the trees are identical return false if not.First we are checking root node of both the trees if both are null then they are identical returning true.

If both root nodes are not null then checking their data.If data is same then recursively traversing on both trees and checking both trees.

else returning false.

5 0

3 years ago

Which layer includes the physical transmission medium (cables or wireless media) that any network must use to send and receive t

Yuliya22 [10]

Answer:

The correct answer to the following question will be "Physical Layer".

Explanation:

The lowest layer of the OSI reference model is the physical layer. It's in charge of having to send bits from one desktop to the next.
This layer isn't acquainted with the interpretation of the parts and is concerned with setting up a physical wireless connection and sending and receiving signals.
This layer relies on aspects of the hardware, such as wires, transmitters, and network interface tokens.

Therefore, it will be the right answer.

4 0

3 years ago

A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter

trapecia [35]

Answer:

5 Letters

Explanation:

So we need 12 distinct codes made of a single letter or a pair of letters.

What would be the least number of letters?

Lets try with 3 letters A, B and C

The possible combinations are: A, B, C, AB, AC, BC

These are 6 codes and we need 12 so lets try more A, B, C and D

The possible combinations are: A, B, C, D, AB, AC, AD, BC, BD, CD

These are 10 codes and we need 12 so lets try more A, B, C, D and E

The possible combinations are:

A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE

Finally we got 15 distinct codes which are more than 12 so the least number of letters needed are 5.

Using formula:

Four letters = 4C1 + 4C2 = 4 + 6 = 10

Five letters = 5C1 + 5C2 = 5 + 10 = 15

5 0

3 years ago

PLS HELP!! 50 Points! Will mark correct answer brainliest!!

Illusion [34]

Answer: C

Explanation:

That way she can have slides for her advance class and leave out slides that her normal class doesn’t need

5 0

3 years ago

Read 2 more answers