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3 years ago

Explain the concept of an engineering trade-offs and give an example

Computers and Technology

2 answers:

makvit [3.9K]3 years ago

8 0

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Deffense [45]3 years ago

8 0

Answer:

- A trade-off is an exchange in which one benefit is given up in order to obtain another.

Example: a material may be used to build a house because it is attractive to customers even though it is not as durable.

yeeeet

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ZipCar uses cutting edge wireless technology combined with sophisticated data management and security techniques to assure that

Bingel [31]

Answer:

dependable

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1 year ago

The number of __________ to your website that had not visited prior to the time frame being analyzed.

liq [111]

Answer:

First Time Unique Visitor

Explanation:

I majored in

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3 years ago

ImmuneEarth, a research and development company, has "eradicate all diseases" as its motto. It has numerous departments that res

anastassius [24]

Answer:

Grid computing.

Explanation:

Grid computing is a study utilizing Immune Earth to test AIDS treatment because the following are the reasons that describe the answer is true about the scenario.

Grid computing seems to be a scattered network with a vast amount for systems linked to handle a difficult issue.
Systems can be linked straightly or through organized systems.

Other options are incorrect.

Green computing is not the correct answer according to the scenario because the usage of systems and its energy is socially safe and economically sustainable.
Trusted Computing is not the correct answer according to the scenario because it helps a part of information to show which os as well as program to be required to access this.
Edge computing is not the correct answer according to the scenario because it optimizes web apps as well as software programs while getting computation back to the information base.

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3 years ago

You have spent $4,000 on liquor for your bar. Your bar sales have been $24,000. What is your cost of sales for liquor, expressed

amid [387]

Answer:

17%

Explanation:

Given parameters:

Cost price of liquor = $4000

Total sale = $24000

Unknown:

Percentage cost of sale for liquor = ?

Solution:

To find the percentage cost of sale;

%Cost of sale of liquor = $\frac{cost price of liquor}{Total cost of sale }$ x 100

Input the variables;

%Cost of sale of liquor = $\frac{4000}{24000}$ x 100 = 16.67% = 17%

8 0

2 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago