All categories

3 years ago

What changes would you make in your description of point, line, and plane?

Mathematics

1 answer:

weeeeeb [17]3 years ago

5 0

Answer:

Here's a quick sketch of how to calculate the distance from a point P=(x1,y1,z1)

(

)

to a plane determined by normal vector N=(A,B,C)

(

)

and point Q=(x0,y0,z0)

(

)

. The equation for the plane determined by N

and Q

is A(x−x0)+B(y−y0)+C(z−z0)=0

(

−

)

(

−

)

(

−

)

, which we could write as Ax+By+Cz+D=0

, where D=−Ax0−By0−Cz0

−

This applet demonstrates the setup of the problem and the method we will use to derive a formula for the distance from the plane to the point P

Step-by-step explanation:

You might be interested in

A computer simulation tossed a 10 faced die 5 times. How many possible outcomes

bulgar [2K]

Answer:

Step-by-step explanation:

10x5=50

8 0

3 years ago

Model to write 30 or 40 as a mixed number

____ [38]

30 as a mixed number:
$10 \frac{200}{10}$

3 0

3 years ago

Just answer don't waste my time. An art class is making a mural for their school which has a triangle drawn in the middle. The l

OLEGan [10]

Answer:

qfgjwtjywkshlshlwykqtj

Step-by-step explanation:

htjyjwjwk4o47orjluothjfrh5qi6woi623o76woeluhsmgsmfanegruq2yiwyjajgafbrhqtj26iwykw5jqrhrhqqrhq5uq5u14uqtjtqjtqjatiatiatiFUFJfbatabtnafbaFJfutjfjbffbafbafjaafjagjqrhqrjafbf r rhaafjfjafabr atanathbra r r rbbb3rhb qtwhwtjwgjwtjqtjqfb hqtjqfbqfb afbqfhqfhafjwtjukdb sg b th2tj h1rhf b rttt r r rbrbrbrvr rvr r r ecscsgj

3 0

3 years ago

Solve each equation (x+8)(x-2)=-9

Nesterboy [21]

X=1, x=-7 would be the correct answer.

5 0

3 years ago

Read 2 more answers

At a certain coffee shop, all the customers buy a cup of coffee and some also buy a doughnut. The shop owner believes that the n

wolverine [178]

Answer:

(1) The probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2) The shop owner has no reasonable chance to expect earning a profit more than $300.

(3) The probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

Step-by-step explanation:

Let X = number of cups of coffee sold and Y = number of donuts sold.

The random variable X follows a Normal distribution with parameters μ = 320 and σ = 20.

The random variable Y follows a Normal distribution with parameters μ = 150 and σ = 12.

The shop owner opens the shop 6 days a week.

(1)

Compute the probability that the shop owner sells over 2000 cups of coffee in a week as follows:

$P(X>2000)=P(\frac{X-\mu}{\sigma}>\frac{2000-(6\times320)}{6\times20})\\=P(Z>0.67)\\=1-P(Z$

Thus, the probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2)

The equation representing the profit earned on selling 1 cup of coffee and 1 doughnut in a day is:

P = 0.5X + 0.4Y

Compute the probability that the shop owner earns more than $300 as profit as follows:

$P(Profit>300)=P(\frac{Profit-\mu}{\sigma}>\frac{300-((0.5\times320)+(0.4\times150))}{\sqrt{0.5^{2}(20)^{2}+0.4^{2}(12)^{2}}})\\=P(Z>7.21)\\\approx0$

The probability of earning a profit more then $300 is approximately 0.

Thus, the shop owner has no reasonable chance to expect earning a profit more than $300.

(3)

The expression representing the statement "he'll sell a doughnut to more than half of his coffee customers" is:

Y > 0.5X

Y - 0.5X > 0

Compute the probability of the event (Y - 0.5X > 0) as follows:

$P(Y - 0.5X > 0)=P(\frac{(Y - 0.5X) -\mu}{\sigma}>\frac{0-(150-(0.5\times320}{\sqrt{12^{2}+0.5^{2}20^{2}}})\\=P(Z>0.64)\\=1-P(Z$

Thus, the probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

8 0

3 years ago