Answer:
Step-by-step explanation:
<u>Given polynomials</u>:
Factor the polynomials:
<u>Polynomial 1</u>
![\implies 3[2x(x+7)-1(x+7)]](https://tex.z-dn.net/?f=%5Cimplies%203%5B2x%28x%2B7%29-1%28x%2B7%29%5D)
<u>Polynomial 2</u>
![\implies 6[x(x+7)+2(x+7)]](https://tex.z-dn.net/?f=%5Cimplies%206%5Bx%28x%2B7%29%2B2%28x%2B7%29%5D)
The lowest common multiplier (LCM) of two polynomials a and b is the <u>smallest multiplier</u> that is <u>divisible</u> by both a and b.
Therefore, the LCM of the two polynomials is:
They cancel each other out because one is + and the other is -.
<span>5 1/6 x 1/3
</span>first convert 5 1/6 (which is a mixed fraction) into an improper fraction ...
=> 6*5+1/6 = 31/6
=>now we have ... 31/6 * 1/3
=> to multiply fractions we multiply the numerators ( top numbers ) with each other and the denominators (bottom numbers ) also the same way ...
=> 31/6 * 1/3 => 31*1 / 6*3 => 31/18
=> then divide them to get answer as mixed fraction ..
=> 1 13/18 ..
<span>3 1/2 / 1 1/3
</span>=> here also first convert 3 1/2 and 1 1/3 into improper fractions ..
=> 3 1/2 => 2*3+1/2 => 7/2
=> 1 1/3 => 3*1+1/3=> 4/3
=> now divide them ..
=> 7/2/4/3
=> for dividing fractions we take the reciprocal of one fraction and then multiply ..
=> 7/2 * 3/4
=> now multiply these two fractions ..
=> 7*3/2*4 => 21/8
=> answer as mixed fraction = 2 5/8 ...
Hope it helps !!!
Answer:
All of the following fractions work: 1/2, 7/12, 8/12. There are endless possibilities.
Please mark as Brainliest! :)
Take
so that you have
which gives a Jacobian determinant of
So upon transforming the coordinates to the u-v plane, you have (and I'm guessing on what the integrand actually is)
