2 years ago

Simplify Question 8 options: A) 8 B) 9 C) 6 D) 12

Mathematics

1 answer:

Gwar [14]2 years ago

5 0

Answer:

Your question is incomplete ..

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In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the nearest degree

Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

$\cos A=\dfrac{b^2+c^2-a^2}{2bc}$

Using Law of Cosines in triangle OPQ, we get

$\cos P=\dfrac{o^2+q^2-p^2}{2oq}$

$\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}$

$\cos P=\dfrac{490000+384400-705600}{868000}$

$\cos P=\dfrac{168800}{868000}$

On further simplification, we get

$\cos P=0.19447$

$P=\cos^{-1}(0.19447)$

$P=78.786236$

$P\approx 79$

Therefore, the measure of angle P is 79 degrees.

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2 years ago

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PLEASE PLEASE PLEASE HELP I NEED HELP WITH THIS :(( i will give brainliest:)

bezimeni [28]

-3+8=5

2-6=-4

-3+-1=-4

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2 years ago

3 1183 long division

Triss [41]

= 394 R 1

= 394 1/3

1183 divided by 3 equals
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2 years ago

Lauren has finished 25% of the 120 push ups she needs to do for softball

Ilya [14]

Answer:

30 pushups

Step-by-step explanation:

25/100 = x/120

so, 120x25 = 100x

3000 = 100x

3000/100= x

x = 30

so, Lauren has completed 30 push-ups.

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2 years ago

Need help with this

netineya [11]

The answer to your question is C.

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2 years ago