Distance = rate*time
distance/time = rate
The race course is 3 miles around and Jeff does it twice, so the distance he goes = 2*3 miles = 6 miles.
He takes 20 minutes to go around once and 25 minutes to go around the second time, so the total time = 20 min + 25 min = 45 min.
His speed is miles per hour, not miles per minute, so convert 45 minutes to a hours:
45 min/60 min = 0.75 hours <span>distance/time = rate = 6 miles/0.75 hours = 8 mph</span>
Answer:
|x-153|=57
Step-by-step explanation:
edmentum
Answer:
or 35.52
Step-by-step explanation:
1. ![\sqrt[3]{2883\sqrt[3]{723\sqrt{27}}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2883%5Csqrt%5B3%5D%7B723%5Csqrt%7B27%7D%7D%7D)
2.
= ![\sqrt[3]{2169}\sqrt[6]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2169%7D%5Csqrt%5B6%5D%7B3%7D)
3. ![\sqrt[3]{2883\sqrt[3]{2169}\sqrt[6]{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2883%5Csqrt%5B3%5D%7B2169%7D%5Csqrt%5B6%5D%7B3%7D%7D)
4.
= ![\sqrt[3]{2883}\sqrt[3]{\sqrt[3]{2169}\sqrt[6]{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2883%7D%5Csqrt%5B3%5D%7B%5Csqrt%5B3%5D%7B2169%7D%5Csqrt%5B6%5D%7B3%7D%7D)
5. So, the answer is ![\sqrt[3]{2883}\sqrt[3]{\sqrt[3]{2169}\sqrt[6]{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2883%7D%5Csqrt%5B3%5D%7B%5Csqrt%5B3%5D%7B2169%7D%5Csqrt%5B6%5D%7B3%7D%7D)
Hope this helps! :)
Answer:
162 each season
Step-by-step explanation:
Your answer will be 0.132