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3 years ago

I really need help on this question! Thank you!

Mathematics

2 answers:

Korolek [52]3 years ago

7 0

The answer for your question is A

KIM [24]3 years ago

5 0

Answer:

Step-by-step explanation:

We know the following:

$OE=5\\\\FG=4\\\\EF=8\\\\$

so the segment EF is equal to

$EF=EG+GO+OF\\\\$

and here we can do a trick :)

$EF=(EG+GO)+GO+(OF+OG)-2GO\\\\$

you see it's the same

$EF=EO-GO+FG\\\\$

now we plug the values given

$8=5-GO+4\\\\8=9-GO\\\\GO=9-8\\\\GO=1$

so it's option A

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mars1129 [50]

Answer:

The 80% confidence interval for difference between two means is (0.85, 1.55).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for difference between two means is:

$CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2,(n_{1}+n_{2}-2)}\times SE_{\bar x_{1}-\bar x_{2}}$

Given:

$\bar x_{1}=M_{1}=6.1\\\bar x_{2}=M_{2}=4.9\\SE_{\bar x_{1}-\bar x_{2}}=0.25$

Confidence level = 80%

$t_{\alpha/2, (n_{1}+n_{2}-2)}=t_{0.20/2, (5+5-2)}=t_{0.10,8}=1.397$

*Use a <em>t</em>-table for the critical value.

Compute the 80% confidence interval for difference between two means as follows:

$CI=(6.1-4.9)\pm 1.397\times 0.25\\=1.2\pm 0.34925\\=(0.85075, 1.54925)\\\approx(0.85, 1.55)$

Thus, the 80% confidence interval for difference between two means is (0.85, 1.55).

3 0

2 years ago

What percent of 3000 is 18??

77julia77 [94]

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3 years ago

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MArishka [77]

Answer:

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2 years ago

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sveticcg [70]

Answer:

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