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Nimfa-mama [501]
3 years ago
12

I really need help on this question! Thank you!

Mathematics
2 answers:
Korolek [52]3 years ago
7 0
The answer for your question is A
KIM [24]3 years ago
5 0

Answer:

A

Step-by-step explanation:

We know the following:

OE=5\\\\FG=4\\\\EF=8\\\\

so the segment EF is equal to

EF=EG+GO+OF\\\\

and here we can do a trick :)

EF=(EG+GO)+GO+(OF+OG)-2GO\\\\

you see it's the same

EF=EO-GO+FG\\\\

now we plug the values given

8=5-GO+4\\\\8=9-GO\\\\GO=9-8\\\\GO=1

so it's option A

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A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo
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<u>SOLUTION: </u>

Given, a rectangle swimming pool is 8 feet deep.  

One side of the pool is 4.5 times longer than the other.  

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,  

\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}

On taking square root on both sides we get,

\begin{array}{l}{\rightarrow\sqrt{n^{2}}=\sqrt{100}} \\\\ {\rightarrow n=10 \mathrm{ft}}\end{array}

So, the width will be 4.5 n=4.5 \times 10=45 \mathrm{ft}

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