1. C
L=1/2(Pxl)
L=1/2(20x9)
L=1/2(180)
L=90
SA=1/2(Pxl)+B
SA=90+5^2
SA=115
B, A, C, B.
Answer:
a. 6
b. 7
c. (b) Kira's
why? b. it has the large sample size
Step-by-step explanation:
Answer:
value of x = 5
Step-by-step explanation:
Given:
∠L = ∠n
So,
ML = MN
So,
3x = x + 10
2x = 10
x = 5
value of x = 5
Answer:
Step-by-step explanation:
We would apply the simple interest formula which is expressed as
I = PRT/100
Where
P = principal or amount borrowed
T = time in years
R = interest rate on amount borrowed.
I = interest paid.
From the given information,
Principal = $3000
T = 3 months = 3/12 = 0.25 years
R = 6 1/2 % = 6.5%
Therefore,
a) the amount that the woman pay for the use of the money is I
I = (3000 × 6.5 × 0.25)/100 = 48.75
b) The amount she repaid to the bank on the due date of the note would be
Principal + interest
= 3000 + 48.75 = $3048.75
For this case we have the following fractions:
![\frac {11} {2}\\\frac {6} {11}](https://tex.z-dn.net/?f=%5Cfrac%20%7B11%7D%20%7B2%7D%5C%5C%5Cfrac%20%7B6%7D%20%7B11%7D)
We must rewrite the fractions, using the same denominator.
We have then:
We multiply the first fraction by 11 in the numerator and denominator:
![\frac {11} {2} \frac {11} {11}](https://tex.z-dn.net/?f=%5Cfrac%20%7B11%7D%20%7B2%7D%20%5Cfrac%20%7B11%7D%20%7B11%7D)
We multiply the second fraction by 2 in the numerator and denominator:
![\frac {6} {11} \frac {2} {2}](https://tex.z-dn.net/?f=%5Cfrac%20%7B6%7D%20%7B11%7D%20%5Cfrac%20%7B2%7D%20%7B2%7D)
Rewriting we have:
For the first fraction:
![\frac {121} {22}](https://tex.z-dn.net/?f=%5Cfrac%20%7B121%7D%20%7B22%7D)
For the second fraction:
![\frac {12} {22}](https://tex.z-dn.net/?f=%5Cfrac%20%7B12%7D%20%7B22%7D)
We note that:
![\frac {121} {22}> \frac {12} {22}](https://tex.z-dn.net/?f=%5Cfrac%20%7B121%7D%20%7B22%7D%3E%20%5Cfrac%20%7B12%7D%20%7B22%7D)
Answer:
The fractions are not equivalent:
![\frac {11} {2}> \frac {6} {11}](https://tex.z-dn.net/?f=%5Cfrac%20%7B11%7D%20%7B2%7D%3E%20%5Cfrac%20%7B6%7D%20%7B11%7D)