QUESTION BELOW PLEASE HELP

The probability that a randomly selected 3-year-old male chipmunk will live to be 4 years old is 0.96516.

mezya [45]

Using the binomial distribution, it is found that there is a:

a) The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

b) The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

c) The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

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For each chipmunk, there are only two possible outcomes. Either they will live to be 4 years old, or they will not. The probability of a chipmunk living is independent of any other chipmunk, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

0.96516 probability of a chipmunk living through the year, thus $p = 0.96516$

Item a:

Two is P(X = 2) when n = 2, thus:

$P(X = 2) = C_{2,2}(0.96516)^2(1-0.96516)^{0} = 0.9315$

The probability that two randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.93153 = 93.153%.

Item b:

Six is P(X = 6) when n = 6, then:

$P(X = 6) = C_{6,6}(0.96516)^6(1-0.96516)^{0} = 0.80834$

The probability that six randomly selected 3-year-old male chipmunks will live to be 4 years old is 0.80834 = 80.834%.

Item c:

At least one not living is:

$P(X < 6) = 1 - P(X = 6) = 1 - 0.80834 = 0.19166$

The probability that at least one of six randomly selected 3-year-old male chipmunks will not live to be 4 years old is 0.19166 = 19.166%. This probability is not unusual, as it is greater than 5%.

A similar problem is given at brainly.com/question/24756209

6 0

2 years ago

4x + y = 46.75 help!!<br> A 8.50<br> B 8.75<br> C 9.50<br> D12.75

WARRIOR [948]

Answer:

d is the answer

Step-by-step explanation:

3 0

3 years ago

A math test is worth 100 points and has 38 problems. each problem is worth either 5 points or 2 points. how many problems of eac

blondinia [14]

Hey there,
There are 2 ways
1st way:
Since there are 8 5 point problems, 38 - 8 = 30, will give you the 2 point problems.

2nd way:
8 x 5 = 40
100 - 40 = 60
60 / 2 = 30
Thus there are 30, 2 point problems.

Hope this helps :))

~Top

4 0

2 years ago

Read 2 more answers

An individual needs a daily supplement of at least 420 units of vitamin C and 170 units of vitamin E and agrees to obtain this s

Ierofanga [76]

Answer:

To obtain equivalent amount from both foods we can eat 10 ounces of Food I and 5 Ounces of food II

To obtain minimum cholesterol, the individual should eat only 21 ounces of food II and zero ounce of food for the daily supplement of the individual

Step-by-step explanation:

Food I contains 32×C + 10×E per ounce

Food II contains 20×C + 14×E

Here we have X × (Food I) + Y × (Food II) = 420 C + 170 E

32·X + 20·Y = 420 C

10·X + 14·Y = 170 E

Therefore

X = 10 and Y = 5

To minimize the cholesterol, we can increase amount of Food II to get

21 ounces of food II gives

420 units of vitamin E and 294 units of vitamin E with 273 units of cholesterol.

3 0

3 years ago

HELPPP ASAPP Bernie's Bars has determined that a granola bar measuring 3 inches long has a z-score of +1 and a granola bar measu

Len [333]

Answer:

Standard deviation of the length of granola bars produced at Bernie's Bars is 0.50

Step-by-step explanation:

We are given the following information in the question:

Formula:

$z_{score} = \displaystyle\frac{x - \mu}{\sigma}$

where,

μ is the mean and σ is the standard deviation.

Putting the values we get:

$\displaystyle\frac{ 3- \mu}{\sigma} = 1\\\\3 = \sigma + \mu\\\\\displaystyle\frac{ 3.5- \mu}{\sigma} = 2\\\\3.5 = 2\sigma + \mu$

Solving the two obtained equations:

Subtracting the two obtained equation, we have:

$3.5-3 = \mu + 2\sigma - \mu -\sigma\\\sigma = 0.5$

Hence, standard deviation of the length of granola bars produced at Bernie's Bars is 0.50

3 0

3 years ago

Read 2 more answers