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hodyreva [135]
3 years ago
8

Graph the following piecewise function and then find the domain.

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

9514 1404 393

Answer:

  domain: (-4, 9)

Step-by-step explanation:

The graph is defined for all points between -4 and 9, but not for those two points. In interval notation, the domain is (-4, 9).

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Help me please thank you
docker41 [41]

After I read the equation, I remembered that anything to the power of 1 is itself. so f(x)=2-9

2-9= -7

therefore, f(x)= -7

if x=1, then the f(x) must be Y

<u><em>therefore, your answer should be y= -7</em></u>

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The length of one side of APTV is given. Use the relationship between the sides of a 30°-60°-90° triangle to find the lengths of
aliina [53]

Answer:

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Step-by-step explanation:

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3 years ago
S t are positive integers
Sindrei [870]

Given:

The expanded form of (x+s)(x-t) is x^2+Kx-40.

Where, s, t, K are positive integers.

To find:

The smallest possible value of K.

Solution:

The expanded form of (x+s)(x-t) is x^2+Kx-40. It means,

(x+s)(x-t)=x^2+Kx-40

x^2-tx+sx-st=x^2+Kx-40

x^2+(s-t)x-st=x^2+Kx-40

On comping both sides, we get

K=s-t              ...(i)

K is a positive integer if s>t.

And

st=40

The factor pairs of 40 are (1,40), (2,20), (4,10), (5,8), (8,5), (10,4), (20,2) and (40,1).

Since s>t, therefore the possible values for (s,t) are (8,5), (10,4), (20,2) and (40,1).

Using (i), find the value of K for each factor pair.

K=8-5=3  

K=10-4=6      

K=20-2=18          

K=40-1=39          

Therefore, the smallest possible value of K is 3.

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Read 2 more answers
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