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Andrews [41]
3 years ago
11

Pls awnser i will give brainliest pls pls

Mathematics
1 answer:
Airida [17]3 years ago
5 0

Answer:

B

Step-by-step explanation:

Divide the smaller numbers in the table by the larger numbers (in this case diameter divided by circumference) and then compare that with the choices.

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Match the two numbers with their least common multiple (LCM).
AysviL [449]

answer is Lcm which is probaly c

7 0
4 years ago
6+n/5=9<br><br> What is happening to the variable? <br><br><br> How do you solve for the variable?
Svetradugi [14.3K]

Answer:

n=15

Step-by-step explanation:

(subtract 6 from both sides of the equation.)

6+n/5=9

6+n/5-6=9-6

(Now you will have to simplify.)

n/5=3

(You will have to multiply all terms by the same value to eliminate fraction denominators.)

n/5=3

5xn/5=5x3

(You will now have to simplify.)

n=15

And that's how you get your answer.

i hope this helps.      :)

7 0
3 years ago
Please Help.....................................................................................................................
Vlada [557]
You have to divide 28 divided by 12 equals 2.3%
6 0
3 years ago
If x = 5 units, y = 6 units, and h = 6 units, find the area of the trapezoid shown above using decomposition. A. 102 square unit
Kitty [74]

Answer:

C. 66 square units

Step-by-step explanation:

The area of the middle rectangle would by base × height, or y × h, or 6 × 6.

The area is 36.

The area for one triangle would 1/2 × base × height.

(But since there are two triangles to solve for, the 1/2 is not necessary, and we can just do base × height again.)

So, it would be x × h, or 5 × 6.

The area is 30.

Combine both areas to get the whole area of 66 units²

3 0
3 years ago
Please help, I will mark!!
Alik [6]

Answer:

d=28.28

Step-by-step explanation:

To calculate the lenght of the diagonal d across the square, we can assume that the square it is compound of two right triangles. So, we can resolve this exercise using The Pythagorean Theorem.

<em>The Pythagorean theorem</em> states that in every right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the respective lengths of the legs. It is the best-known proposition among those that have their own name in mathematics.

If in a right triangle there are legs of length a and b, and the measure of the hypotenuse is c, then the following relation is fulfilled:

a^{2} +b^{2} =c^{2} a is the height, b is the base, and c is  

the hypotenuse.

To obtain the value of the hypotenuse

c= \sqrt{a^{2} +b^{2} }

To find the value of the lenght of the diagonal d across the square, we have:

d=\sqrt{a^{2} +b^{2} } Where a = b = 20

Substituting the values

d=\sqrt{(20)^{2} +(20)^{2} }\\d=\sqrt{400+400} =\sqrt{800} \\d=28.284

Round the answer to 2 decimal places

d=28.28

6 0
3 years ago
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