See the attached figure.
m ∠KAJ = 170° & m ∠LAM = 80°
We should know that :
m ∠KAJ + m ∠LAM + m ∠KAL + m ∠MAJ = 360°
∴ m ∠KAL + m ∠MAJ = 360° - (m ∠KAJ + m ∠LAM)
∴ m ∠KAL + m ∠MAJ = 360° - (170°+80°) = 360° - 250° = 110°
But : m ∠KAL = m ∠MAJ ⇒⇒⇒ <u>Opposite angles.</u>
∴ m ∠MAJ + m ∠MAJ = 110°
∴ 2 * m ∠MAJ = 110°
∴ m ∠MAJ = 110° ÷ 2 = 55°
<u>So, the answer is : m ∠MAJ = 55°</u>
Answer:
BC = 17.2.
Step-by-step explanation:
Since CAB = 90º, this is a right triangle.
The triangle format is given below:
C
A B
We have that AB = 8.6, and angle B measures 60º.
Length of BC:
BC is the hypotenyse.
Side AB is adjacent to angle B = 60º.
In a right triangle, angle , it's adjacent side with length s and the hypotenuse h are related by the cosine of the angle, that is:
In this question, we have an angle of 60º, with has cosine 0.5. We also have that side AB = s = 8.6, and the hypotenuse h is side BC. So
BC = 17.2.
Answer:
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Answer:
125 = 5 x 5 x 5 or 125 = 5³
Step-by-step explanation: