3 years ago

What is the quotient of the following?

1 answer:

3 0

1)22.578/2.13=10.6
2)659*95=62605
3)B. Numbers get smaller as you move to the left on the number line.

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Find the value of x in the figure. 57° (x+23) X =

Lapatulllka [165]

Answer:

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Step-by-step explanation:

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2 years ago

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Given the prelim age point A(-5,3) find the image point A’ using the translation rule (x,y) —> (x+3,y-2)

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Answer:

(-6,4)

Step-by-step explanation:

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A positive B negative C none D multiple

egoroff_w [7]

The answer is positive because its is going in the positive column

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The core melt- down and explosions at the nuclear reactor in Chernobyl in 1986 released large amounts of strontium-90, which dec

elena-14-01-66 [18.8K]

If $S(t)$ is the amount of strontium-90 present in the area in year $t$ , and it decays at a rate of 2.5% per year, then

$S(t+1)=(1-0.025)S(t)=0.975S(t)$

Let $S(0)=s$ be the starting amount immediately after the nuclear reactor explodes. Then

$S(t+1)=0.975S(t)=0.975^2S(t-1)=0.975^3S(t-2)=\cdots=0.975^{t+1}S(0)$

or simply

$S(t)=0.975^ts$

So that after 50 years, the amount of strontium-90 that remains is approximately

$S(50)=0.975^{50}s\approx0.282s$

or about 28% of the original amount.

We can confirm this another way; recall the exponential decay formula,

$S(t)=se^{kt}$

where $t$ is measured in years. We're told that 2.5% of the starting amount $s$ decays after 1 year, so that

$0.975s=se^k\implies k=\ln0.975$

Then after 50 years, we have

$S(50)=se^{50k}\approx0.282s$

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3 years ago

How do you solve for LMN? I keep getting 15

Marina86 [1]

Answer:

60°

Step-by-step explanation:

90° = 6x

15° = x

60° = 4x

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