Answer:
1) It is geometric
a) In each trial you can obtain 11 or obtain something else (and fail)
b) Throw 2 dices and watch if the result is 11 or not
c) The probability of success is 1/18
2) It is not geometric, but binomal.
Step-by-step explanation:
1) This is effectively geometric. When you see the sum of 2 dices, you can separate the result in two different outcomes: when the sum is 11 and when the sum is different from 11.
A trial is constituted bu throwing 2 dices and watching if the sum of the dices is 11 or not.
In order to get 11 you need one 5 in one dice and 1 six in another. As a consecuence, you have 2 favourable outcomes (a 5 in the first dice and a 6 in the second one or the other way around). The total amount of outcomes is 6² = 36, and all of them have equal probability. This means that the probability of success is 2/36 = 1/18.
2) This is not geometric distribution. The geometric distribution meassures how many tries do you need for one success. The amount of success in 10 trias follows a binomial distribution.
Step-by-step explanation:
C=b/a
c=kb/a
where as k is the constant
c=kb/a
we substitute
33=22k/6
crossed multiply
33*6= 22k
198=22k
we divide both sides by 22
198/22=22k/22
K=9
The answer is 128.605 m^2
Answer:
1st odd = 57
2nd odd = 59
3rd odd = 61
Step-by-step explanation:
Suppose the numbers to be:
1st odd = x -2
2nd odd = x
3rd odd = x +2
Now according to given conditions:
1st odd + 2nd odd + 3rd odd = 177
x - 2 + x +x + 2 = 177
By add -2 and + 2 will be cancelled
Adding all x
3x = 177
Dividing both sides by 3 we get
x = 177 / 3
x = 59
Now putting x = 59 to get three consecutive odds:
1st odd = x -2 = 59 - 2 = 57
2nd odd = x = 59
3rd odd = x +2 = 59 + 2 = 61
Proof:
1st odd + 2nd odd + 3rd odd = 177
57 + 59 + 61 = 177
177 = 177
hence proved
I hope it will help you!
C because you need to use the formula and then calculate
