Question

PLEASE HELP!! Find the area of the sector.

Answer 1

Answer:

B.

$\frac{275\pi}{6} {m}^{2}$

Step-by-step explanation:

$area \: of \: sector \: is \\ \frac{the \: angle}{360} \times \pi {r}^{2} \\ hence \: we \: have \\ \frac{165}{360} \times {(10m)}^{2} = \frac{275\pi}{6} {m}^{2}$