Write the set of points from -6 to 0 but excluding -4 and 0 as a union of intervals
First we take the interval -6 to 0. In that -4 and 0 are excluded.
So we split the interval -6 to 0.
Start with -6 and go up to -4. -4 is excluded so we break at -4. Also we use parenthesis for -4.
Interval becomes [-6,-4) . It says -6 included but -4 excluded.
Next interval starts at -4 and ends at 0. -4 and 0 are excluded so we use parenthesis not square brackets
(-4,0)
Now we take union of both intervals
[-6,-4) U (-4,0) --- Interval from -6 to 0 but excluding -4 and 0
Answer:
a = -10
Step-by-step explanation:
-0.4a + 3 = 7
subtract 3 from each side
-0.4a + 3-3 = 7-3
-.4a = 4
Divide each side by -.4
-.4a/ -.4 = 4/-.4
a = - 10
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Answer:
Step-by-step explanation:
The two triangles are congruent.
∠L ≅ ∠ B Given
LN ≅ BZ Given
∠N ≅∠Z Given
ΔLNM ≅ ΔBZA Angle Side Angle congruent
This question is a little unclear. y= 4x - 3 is already in slope-intercept form. If you use (2,-3), then it would look like -3 = 4(2) - 3...