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2 years ago

What is the value of x, when 3x^2=18 3/4?

Mathematics

1 answer:

leva [86]2 years ago

7 0

Answer:

Option B is correct

Step-by-step explanation:

We need to solve the equation 3x^2 = 18 3/4 to find the value of x

3x^2 = 18 3/4

Converting mixed fraction into fraction form

3x^2 = 75/4

Dividing both sides by 3

3x^2/3 = 75/4*3

x^2 = 75/12 (dividing numerator and denominator by 3 which is common factor)

x^2 = 25/4

Taking square root on both sides to find value of x

√x^2 = √25/4

x = ± 5/2

x = ± 2 1/2

So, Option B is correct.

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Katherine invested $86,000 in an account paying an interest rate of 52%

earnstyle [38]

Answer: $4,331‬

Step-by-step explanation:

I will assume that the question meant 5.2% not 52% as this is quite excessive.

Katherine after 13 years.

Convert the variables;

n = 13 years = 13 * 365 = ‭4,745‬ days

r = 5.2% = 5.2/365 = 5.2/365%

Future value = P * ( 1 + r)^n

= 86,000 * (1 + 5.2/365%)⁴⁷⁴⁵

= $169,068

Michael after 13 years;

If compounded continuously, the formula is;

Future value = Pe^rt

= 86,000 * e⁰.⁰⁵ ˣ ¹³

= $164,737

Difference = 169,068 - 164,737

= $4,331‬

5 0

2 years ago

Translate this sentence into an equation.

kakasveta [241]

Answer:

21+j=55

Step-by-step explanation:

It says sum, which means to add(+). So you add 21 and j (21+j) and that equals 55 (=55). Then you add all the pieces together and you get 21+j=55

7 0

3 years ago

Please help as soon as possible

eduard

Answer:

it's 96ft squared hope it helps

4 0

3 years ago

Read 2 more answers

I know that real numbers consist of the natural or counting numbers, whole numbers, integers, rational numbers and irrational nu

ra1l [238]

The imaginary unit $i$ belongs to the set of complex numbers, denoted by $\mathbb C$ . These numbers take the form $a+bi$ , where $a,b$ are any real numbers.

The set of real numbers, $\mathbb R$ , is a subset of $\mathbb C$ , where each number in $\mathbb R$ can be obtained by taking $b=0$ and letting $a$ be any real number.

But any number in $\mathbb C$ with non-zero imaginary part is not a real number. This includes $i$ .

"is it possible that i can use an imaginary number for a real number"

I'm not sure what you mean by this part of your question. It is possible to represent any real number as a complex number, but not a purely imaginary one. All real numbers are complex, but not all complex numbers are real. For example, 2 is real and complex because $2=2+0i$ .

There are some operations that you can carry out on purely imaginary numbers to get a purely real number. A famous example is raising $i$ to the $i$ -th power. Since $i=e^{i\pi/2}$ , we have

$i^i=\left(e^{i\pi/2}\right)^i=e^{i^2\pi/2}=e^{-\pi/2}\approx0.2079$

3 0

3 years ago

What’s the domain and range of y=x^2+2

denpristay [2]

Answer:

domain: all real numbers

range: {y element R : y>=2}

Step-by-step explanation:

7 0

3 years ago