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myrzilka [38]
3 years ago
6

The product of 2x^3 and 6x^5 is

Mathematics
1 answer:
Butoxors [25]3 years ago
3 0
12x^8 multiply the leading terms (2and 6) then add exponents (5and3)
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The tree diagram below shows all of the possible outcomes for flipping three coins.
Pepsi [2]

Answer:

5

Step-by-step explanation:

Ghhjj fun in jjhv GUI gh

3 0
3 years ago
Find 2 consecutive odd integers whose sum is 116
zysi [14]
If you add the numbers 57 and 59 together you get 116
8 0
3 years ago
Read 2 more answers
Please keep as simple as possible
Alenkinab [10]

Answer:

f(x) = (X^3 +6) + 4

Step-by-step explanation:

to move left add +6 from <u>inside</u> the parenthesis

to move up add +4 <u>outside</u> of parenthesis

<em>*since there were no parenthesis you add them*</em>

7 0
3 years ago
Read 2 more answers
Plz plz help me so i can get a good grade
Levart [38]

Area of the figure = 806.5 in²

Solution:

Length of the rectangle = 16 in

Breadth of the rectangle = 9 in

Area of the rectangle = length × breadth

                                    = 16 × 9

Area of the rectangle = 144 in²

Base of the triangle = 31 in

Height of the triangle = 20 in

Area of the triangle = \frac{1}{2}bh

                                 $=\frac{1}{2}\times 31\times 20

Area of the triangle = 310 in²

Parallel sides of the trapezium = 16 in and 31 in

Height of the trapezium = 35 – 20 = 15 in

Area of the trapezium = \frac{1}{2}\times \text{Sum of the parallel sides}\times \text{Height}

                                     $=\frac{1}{2}\times {(16+31)}\times{15}

                                     $=\frac{1}{2}\times {47}\times{15}

Area of the trapezium = 352.5 in²

Area of the figure = Area of rectangle + Area of triangle + Area of trapezium

                              = 144 in² + 310 in² + 352.5 in²

Area of the figure = 806.5 in²

8 0
3 years ago
A. −1≤x&lt;0<br> B. 1≤x≤2<br> C. 0 D. −1≤x≤5
marishachu [46]

Answer: C

Step-by-step explanation:

4 0
2 years ago
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