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Rzqust [24]
3 years ago
11

The product of twice a number and four is the same as the difference of seven times the number and 5/3

Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

2N÷4=7N-5/3

Hope this helps!

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6x2 + 12x + 2 = -10<br> Quadratic equation solve
Pani-rosa [81]
Add 10 on both sides

6x^2+12x+12=0.

Divide by 6 on both sides.

X^2+2x+2=0

Plug into quadratic formula

X=(-2 +\- (2^2-4•1•2))^1/2) /2•1
X=(-2 +\- (-4)^1/2)/2
X=(-2+\- 2i) /2
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7 0
3 years ago
0.2(×+50) -6=0.4(3×+20) need work
Alina [70]

Hey there!

Given equation :

... 0.2 ( x + 50 ) - 6 = 0.4 ( 3x + 20 )

Using the distributive property.

... 0.2x + 10 - 6 = 1.2x + 8

... 0.2x + 4 = 1.2x + 8

Subtract 4 on both sides.

... 0.2x = 1.2x + 4

Subtract 1.2x on both sides.

... - x = 4

... x = -4

Hence, the answer is -4.

Hope it helps!!

6 0
4 years ago
Read 2 more answers
) 10 counters in a bag. 4 red, 3 green, 2 pink and 1 blue. Ella picks a counter at random from the bag, notes the colour and the
Fofino [41]

Answer:

a) i) The probability depends on the total number of counters not on the number of colors.

  ii) There are 10 number of counters not 4

b) \dfrac{3}{10}

Step-by-step explanation:

Given that:

Total number of counters in a bag = 10

Number of red counters = 4

Number of green counters = 3

Number of pink counters = 2

Number of blue counters = 1

a) Ella writes: "There are four colors, so the probability of selecting a green is \frac{1}4 + \frac{1}4 = \frac{2}4 , so the probability is \frac{1}2"

Ella has considered the total type of counters here, which is 4.

But Ella must have considered total number of counters which is 10.

  i) The probability depends on the total number of counters not on the number of colors.

  ii) There are 10 number of counters not 4

b) There are 4 colors in the bag.

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

To select 2 counters of the same color:

P(2\ red) = \dfrac{4}{10}\times \dfrac{4}{10} = \dfrac{16}{100}

P(2\ green) = \dfrac{3}{10}\times \dfrac{3}{10} = \dfrac{9}{100}

P(2\ pink) = \dfrac{2}{10}\times \dfrac{2}{10} = \dfrac{4}{100}

P(2\ blue) = \dfrac{1}{10}\times \dfrac{1}{10} = \dfrac{1}{100}

The required probability will be the sum of all 4 above probabilities:

P(2\ of\ same\ color) = \dfrac{30}{100} = \bold{\dfrac{3}{10} }

6 0
3 years ago
Evaluate the function for the given domain. f(1) = -2x + 1
madam [21]
ANSWER -

-1


EXPLANATION - any expression multiplied by 1 remains the same
6 0
3 years ago
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