<u>Given</u>:
The 11th term in a geometric sequence is 48.
The 12th term in the sequence is 192.
The common ratio is 4.
We need to determine the 10th term of the sequence.
<u>General term:</u>
The general term of the geometric sequence is given by

where a is the first term and r is the common ratio.
The 11th term is given is 

 ------- (1)
 ------- (1)
The 12th term is given by
 ------- (2)
 ------- (2)
<u>Value of a:</u>
The value of a can be determined by solving any one of the two equations.
Hence, let us solve the equation (1) to determine the value of a.
Thus, we have;

Dividing both sides by 1048576, we get;

Thus, the value of a is 
<u>Value of the 10th term:</u>
The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term  , we get;
, we get;





Thus, the 10th term of the sequence is 12.
 
        
             
        
        
        
Answer: P=130
2W +2L=130
2(31) + 2(34)=130
W=31
L=34
Step-by-step explanation:
P=130
2L + 2W
W=L-3
Add all of the sides together to get perimeter.
2(L-3) + 2L=130
2L-6+2L=130
4L-6+6=130+6
4L=136
4L/4=136/4
L=34
W=L-3
W=34-3
W=31
 
        
             
        
        
        
Since only one person can finish in first place, one in second, etc., the total number of placers is 12x11x10, or 1320 different ways the 12 racers can finish 1st, 2nd and 3rd....
☺☺☺☺
        
                    
             
        
        
        
Answer:
Step-by-step explanation: