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Pani-rosa [81]
3 years ago
13

How many times greater is 3.8 X 10^5 than 1.9 X 10^2 2 20 200 2000

Mathematics
2 answers:
creativ13 [48]3 years ago
8 0
2000 is the answer

1.9 x 10^2= 190
3.8 x 10^5= 380000

Answers:
x2= 380
x20= 3800
x200= 38000
x2000= 380000

Correct Answer: 2000
storchak [24]3 years ago
6 0

Answer:

2 * 10^3 = 2000.

Step-by-step explanation:

3.8/1.9 * 10^5/10^2

= 2 * 10^3

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the 11th term in a geometric sequence is 48 and the common ratio is 4. the 12th term is 192 and the 10th term is what?
Soloha48 [4]

<u>Given</u>:

The 11th term in a geometric sequence is 48.

The 12th term in the sequence is 192.

The common ratio is 4.

We need to determine the 10th term of the sequence.

<u>General term:</u>

The general term of the geometric sequence is given by

a_n=a(r)^{n-1}

where a is the first term and r is the common ratio.

The 11th term is given is

a_{11}=a(4)^{11-1}

48=a(4)^{10} ------- (1)

The 12th term is given by

192=a(4)^{11} ------- (2)

<u>Value of a:</u>

The value of a can be determined by solving any one of the two equations.

Hence, let us solve the equation (1) to determine the value of a.

Thus, we have;

48=a(1048576)

Dividing both sides by 1048576, we get;

\frac{3}{65536}=a

Thus, the value of a is \frac{3}{65536}

<u>Value of the 10th term:</u>

The 10th term of the sequence can be determined by substituting the values a and the common ratio r in the general term a_n=a(r)^{n-1}, we get;

a_{10}=\frac{3}{65536}(4)^{10-1}

a_{10}=\frac{3}{65536}(4)^{9}

a_{10}=\frac{3}{65536}(262144)

a_{10}=\frac{786432}{65536}

a_{10}=12

Thus, the 10th term of the sequence is 12.

8 0
3 years ago
If the width of a rectangle is 3 yards less than it’s length and the perimeter is 130 yards, what is the length and the width.
Marianna [84]

Answer: P=130

2W +2L=130

2(31) + 2(34)=130

W=31

L=34

Step-by-step explanation:

P=130

2L + 2W

W=L-3

Add all of the sides together to get perimeter.

2(L-3) + 2L=130

2L-6+2L=130

4L-6+6=130+6

4L=136

4L/4=136/4

L=34

W=L-3

W=34-3

W=31



6 0
3 years ago
Twelve runners are competing in a race. In how many different ways can the first,second,and third place trophies be awarded
zubka84 [21]
Since only one person can finish in first place, one in second, etc., the total number of placers is 12x11x10, or 1320 different ways the 12 racers can finish 1st, 2nd and 3rd....
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8 0
3 years ago
Read 2 more answers
PLEASE HELP I HAVE 45 min to SUBMIT WILL GIVE BRAINLESSLY
luda_lava [24]

Answer:

Step-by-step explanation:

3 0
2 years ago
Toby invested £7500 for 2 years in a savings account. he was paid 4% per annum compound interest. how much money did Toby have a
Oduvanchick [21]
A=7,500×(1+0.04)^(2)
A=8,112
7 0
3 years ago
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