2 years ago

Hdndnndndndndnndndndndnbd

Mathematics

1 answer:

ipn [44]2 years ago

8 0

Answer:

Hshushahhahaa

Hdhddjkddjdkjd

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Elanso [62]

The top answer on your screen is the answer. Hope this help

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3 years ago

John is paid 5% commission on the value of photocopiers he sells. Last week he sold $24,000 worth of copiers. He decided to inve

allsm [11]

Answer:

5040

Step-by-step explanation:

24000-5%=1200

1200+5%=1260

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3 years ago

A student determined the value of x as shown. Explain the students error. (Click on photo and NO ABSOLUTELY NO LINKS)

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Step-by-step explanation:

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2 years ago

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xenn [34]

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3 years ago

Read 2 more answers

See question in attached photo.

statuscvo [17]

9514 1404 393

Answer:

(a, b) = (-2, -1)

Step-by-step explanation:

The transpose of the given matrix is ...

$A^T=\left[\begin{array}{ccc}1&2&a\\2&1&2\\2&-2&b\end{array}\right]$

Then the [3,1] term of the product is ...

$(A\cdot A^T)_{31}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}1&2&2\end{array}\right]=a+2b+4$

and the [3,2] term is ...

$(A\cdot A^T)_{32}=\left[\begin{array}{ccc}a&2&b\end{array}\right]\cdot\left[\begin{array}{ccc}2&1&-2\end{array}\right]=2a-2b+2$

Both of these terms in the product matrix are 0. We can solve the system of equations by adding these two terms:

(a +2b +4) +(2a -2b +2) = (0) +(0)

3a +6 = 0

a = -2

Substituting for 'a' in term [3,1] gives ...

-2 +2b +4 = 0

b = -1

The ordered pair (a, b) is (-2, -1).

8 0

2 years ago