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uranmaximum [27]
3 years ago
11

\\x^{2} + 3\\x - 2" alt="if x = -5\\x^{2} + 3\\x - 2" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

this question is inappropriate

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Negative three times the sum of two times a number and 1 is equal to 5.” Write an equation that represents the equation, then so
Kamila [148]

So, we need to consider what is being done.


So, lets start with the -3.


-3*


Now, lets see what's next

2 times a number is the same as saying 2x, then add one.


That is equal to five.  

-3(-2x+1)=5

Now,

6x-3 = 5

6x = 8

x= 8/6

8 0
3 years ago
Answer both for brainliest and 20 pts
Nata [24]

Answer:

ed = 3

lm = 30.6

Step-by-step explanation:

5 0
3 years ago
A law firm is going to designate associates and partners to a big new case. The daily rate charged to the client for each associ
Vera_Pavlovna [14]

Answer:

$8700

Step-by-step explanation:

Associates cost $800 each, you have 9 associates, so multiply 800 by 9 which gives you: $800x 9= $7200.

Partners cost $1500 each, you have 4 partners, so multiply 1500 by 4 which gives you: $1500x 4=$6000.

Then add the two together like this: $7200+$1500= $8700.

8 0
3 years ago
Read 2 more answers
If fx = 3x over 5 +3 which of the following is the inverse
Alborosie

Answer:

f^(-1)(x) = -3x/(3x-3)

Step-by-step explanation:

1) replace f(x) by y

● y = 3x/(5x+3)

2) exchange x and y

● y = 3x/(5x+3)

● x = 3y / (3y +3)

3) solve for y

● x = 3y / (3y +3)

● x (3y +3) = 3y

● 3xy + 3x = 3y

● 3xy - 3y = -3x

● y (3x - 3) = -3x

● y = -3x /(3x-3)

4) replace y with f^(-1)(x)

● y = -3x/(3x-3)

● f^(-1)(x) = -3x/(3x-3)

3 0
3 years ago
The Magazine Mass Marketing Company has received 10 entries in its latest sweepstakes. They know that the probability of receivi
Serjik [45]

Answer:

P(X>4)= 0.624

Step-by-step explanation:

Given that

n = 10

p= 0.5 ,q= 1 - p = 0.5

Two fifth of 10 = 2/5 x 10 =4

It means that we have to find probability P(X>4).

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

We know that

P(X=x)=(_{x}^{n})\ p^xq^{n-x}

P(X=0)=(_{0}^{10})\ 0.5^0\ 0.5^{10}=0.0009

P(X=1)=(_{1}^{10})\ 0.5^1\ 0.5^{9}=0.0097

P(X=2)=(_{2}^{10})\ 0.5^2\ 0.5^{8}=0.043

P(X=3)=(_{3}^{10})\ 0.5^3\ 0.5^{7}=0.117  

P(X=4)=(_{4}^{10})\ 0.5^3\ 0.5^{7}=0.205

P(X>4)= 1 -P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)

P(X>4)= 1 -0.0009 - 0.0097 - 0.043 - 0.117-0.205

P(X>4)= 0.624

8 0
3 years ago
Read 2 more answers
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