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andreyandreev [35.5K]
3 years ago
10

Find the slope of the line.

Mathematics
1 answer:
nadya68 [22]3 years ago
5 0

Answer:

Formula: Y=mx+b...

Step-by-step explanation:

Y=mx+b

  • M= Rise over run = 1/1
  • b=y-intercept=0

Answer: Y=1x

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A limo driver needs to make more than $450 in one day. He charges a rental fee of $375 and $0.85 per mile. What inequality repre
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Answer:

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Step-by-step explanation:

0.85x + 375 > 450

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What is the area of the triangle (-5,-2) (3,-1)
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idk

Step-by-step explanation:

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3 years ago
A cash card has a starting value of $25. If the card is not used within the first year of its purchase, the value on the card be
densk [106]

Answer:

Discrete; number of Months after the first year; amount remaining on the card.

Step-by-step explanation:

The value of the card strictly loses $2.50/month after the first year of purchase. This means that the values can only be $22.50, $20, etc. If it were continuous, it would lose an amount that led up to $2.50, meaning that you could have values such as $23.48 and $24.07. We cannot have these values, therefore the relationship is discrete.

As time passes, the amount of money in the card changes. As the amount of money in the card depends on the number of months, we can say that the number of months is the independent variable while the amount of money on the card is the dependent variable.

Hope this helps.

8 0
3 years ago
Read 2 more answers
What is the radius with an area of 2.25cm squared?​
vlada-n [284]

Answer:

9 centimeters He said squared And radius...

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8 0
3 years ago
An investment services company experienced dramatic growth in the last two decades. The following models for the company's reven
zlopas [31]

Answer: a) 138.32 and b) 35 years approx.

Step-by-step explanation:

Since we have given that

R(t)=21.4e^{0.13t}\\\\C(t)=18.6e^{0.13t}

So, Profit is given by

Profit=R(t)-C(t)\\\\Profit=21.4e^{0.13t}-18.6e^{0.13t}\\\\Profit=e^{0.13t}(21.4-18.6)\\\\Profit=2.8e^{0.13t}

Difference in years of 1990 and 2020=30

So, Profit becomes :

P(30)=2.8e^{0.13\times 30}\\\\P(30)=2.8\times 49.40\\\\P(30)=138.32

(b) How long before the profit found in part (a) is predicted to double? (Round your answer to the nearest whole number.) years after 1990.

So, profit doubles , we get :

138.32\times 2=2.8e^{0.13t}\\\\276.65=2.8e^{0.13t}\\\\\dfrac{276.65}{2.8}=e^{0.13t}\\\\98.80=e^[0.13t}\\\\\ln 98.80=0.13t\\\\4.593=0.13t\\\\\dfrac{4..593}{0.13}=t\\\\35.33=t

Hence, a) 138.32 and b) 35 years approx.

6 0
3 years ago
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