I would say that the answer is (-0.5,1).
Hope this helped!
See picture reply for answer.
Answer:
<em>795.596≤u≤804.403</em>
Step-by-step explanation:
Confidence interval is expressed using the formula;
CI = xbar ± (z*s/√n)
xbar is the sample mean
z is the z score at 98% confidence
s is the standard deviation
n is the sample size
Given
xbar = 800
z = 2.33
s = 10
n = 28
Substitute into the formula;
CI =800 ± (2.33*10/√28)
CI = 800 ± (2.33*10/5.2915)
Ci = 800± (2.33* 1.8898)
CI = 800 ± 4.4033
CI = (800-4.4033, 800 + 4.4033)
CI = (795.596, 804.403)
<em>Hence an interval estimate of u with 98% confidence is expressed as </em>
<em>795.596≤u≤804.403</em>
Here the concept is that we use’l’ to represent the numbers but for number 5 we use 4’l’and we use 1 ’/‘ to represent the number 5 For example:
Your equation is gonna be
4.5a + 2.5b = 4.25
I forgot how lol but you gotta now solve for A and B.
