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Yanka [14]
3 years ago
12

What is experience?

Physics
2 answers:
Liula [17]3 years ago
7 0

Answer:

B or D I thinks but not sure

Artemon [7]3 years ago
3 0

Answer:

Skills you developed with practice

Explanation:

Experience by definition means, "practical contact with and observation of facts or events."

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A rectangular pane of glass is 91.1 cm wide and 155.9 cm long, and its area is equal to the length multiplied by the width. Usin
Kamila [148]
911.1×155.9 = 14,202.49
14,202.49 in 3 significant figures would be either 14,200 or 1.42×10^4
8 0
3 years ago
Read 2 more answers
How much force does it take to accelerate a 3.50 kg mass from 3.00 m/s to 17.0 m/s in a time of 2.00 seconds?
zheka24 [161]

Answer:

Force = 24.5 Newton

Explanation:

Given the following data;

Mass = 3.50 kg

Initial velocity, u = 3 m/s

Final velocity, v = 17 m/s

Time, t = 2 seconds

To find the force;

First of all, we would determine the acceleration of the object using the formula;

Acceleration = (v - u)/t

Acceleration = (17 - 3)/2

Acceleration = 14/2

Acceleration = 7 m/s²

Now, we can find the force using the formula;

Force = mass * acceleration

Force = 3.5 * 7

Force = 24.5 Newton

5 0
4 years ago
In your own words explain the importance of the cycles to an ecosystem and how the cycles of matter differ from the flow of ener
Rina8888 [55]
The three main cycles of an ecosystem are the water cycle, the carbon cycle and the nitrogen cycle.
8 0
3 years ago
A uniform electric field is produced due to the charge distribution inside the closed cylindrical surface. (a) What type of char
DiKsa [7]

Answer with Explanation:

a. Option d is true.

a negatively charged plane parallel to the end faces of the cylinder

b. Radius of cylinder, r=0.66m

Magnitude of electric field, E=300 N/C

We have to find the net flux through the closed surface.

Net electric flux,\phi=-2 EA=-2E(\pi r^2)

\phi=-2\times 300\times (3.14\times (0.66)^2)

\phi=-820.67 Nm^2/C

c.

Net charge,Q=\epsilon_0\times \phi

Where

\epsilon_0=8.85\times 10^{-12}

Q=-820.67\times 8.85\times 10^{-12}

Q=-7.26\times 10^{-9} C

Q=-7.26nC

Where 1nC=10^{-9}C

7 0
3 years ago
A bullet of mass 0.0021 kg initially moving at 497 m/s embeds itself in a large fixed piece of wood and travels 0.65 m before co
alina1380 [7]

Answer:

The force exerted by the wood on the bullet is 399.01 N

Explanation:

Given;

mass of bullet, m = 0.0021 kg

initial velocity of the bullet, u = 497 m/s

final velocity of the bullet, v = 0

distance traveled by the bullet, S = 0.65 m

Determine the acceleration of the bullet which is the deceleration.

Apply kinematic equation;

V² = U² + 2aS

0 = 497² - (2 x 0.65)a

0 = 247009 - 1.3a

1.3a = 247009

a = 247009 / 1.3

a = 190006.92 m/s²

Finally, apply Newton's second law of motion to determine the force exerted by the wood on the bullet;

F = ma

F = 0.0021 x 190006.92

F = 399.01 N

Therefore, the force exerted by the wood on the bullet is 399.01 N

6 0
3 years ago
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