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3 years ago

How much force does it take to accelerate a 3.50 kg mass from 3.00 m/s to 17.0 m/s in a time of 2.00 seconds?

Physics

1 answer:

zheka24 [161]3 years ago

5 0

Answer:

Force = 24.5 Newton

Explanation:

Given the following data;

Mass = 3.50 kg

Initial velocity, u = 3 m/s

Final velocity, v = 17 m/s

Time, t = 2 seconds

To find the force;

First of all, we would determine the acceleration of the object using the formula;

Acceleration = (v - u)/t

Acceleration = (17 - 3)/2

Acceleration = 14/2

Acceleration = 7 m/s²

Now, we can find the force using the formula;

Force = mass * acceleration

Force = 3.5 * 7

Force = 24.5 Newton

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An air-filled parallel-plate capacitor has plates of area 2.30 cm2 2 separated by 1.50 mm. The capacitor is connected to a 12.0-

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Answer:

$1.357\times 10^{-12}$

Explanation:

Relevant Data provided

Area which indicates A = 2.3 cm^2 = 2.3 x 10^-4 m^2

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According to the requirement, the computation of value of its capacitance is shown below:-

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n200080 [17]

Answer:

$10.63952sin(209.43951t)$

10.63952 V

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Alternator angular speed is given by

$N_a=2\times \omega_e\\\Rightarrow N_a=2\times 1\times 10^{3}\\\Rightarrow N_a=2\times 10^{3}\ rpm$

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The function is $10.63952sin(209.43951t)$

The induced maximum emf is 10.63952 V

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3 years ago