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LenKa [72]
3 years ago
6

How much force does it take to accelerate a 3.50 kg mass from 3.00 m/s to 17.0 m/s in a time of 2.00 seconds?

Physics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

Force = 24.5 Newton

Explanation:

Given the following data;

Mass = 3.50 kg

Initial velocity, u = 3 m/s

Final velocity, v = 17 m/s

Time, t = 2 seconds

To find the force;

First of all, we would determine the acceleration of the object using the formula;

Acceleration = (v - u)/t

Acceleration = (17 - 3)/2

Acceleration = 14/2

Acceleration = 7 m/s²

Now, we can find the force using the formula;

Force = mass * acceleration

Force = 3.5 * 7

Force = 24.5 Newton

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A uniform rod of length L rests on a frictionless horizontal surface. The rod pivots about a fixed frictionless axis at one end.
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Answer:

A) ω = 6v/19L

B) K2/K1 = 3/19

Explanation:

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Ib = MbRb²

Radius of rotation of bullet Rb = L/2

A) From conservation of angular momentum,

L1 = L2

(Mb)v(L/2) = (Ir+ Ib)ω2

Where Ir is moment of inertia of rod while Ib is moment of inertia of bullet.

(Mr/4)(vL/2) = [(1/3)(Mr)L² + (Mr/4)(L/2)²]ω2

(MrvL/8) = [((Mr)L²/3) + (MrL²/16)]ω2

Divide each term by Mr;

vL/8 = (L²/3 + L²/16)ω2

vL/8 = (19L²/48)ω2

Divide both sides by L to obtain;

v/8 = (19L/48)ω2

Thus;

ω2 = 48v/(19x8L) = 6v/19L

B) K1 = K1b + K1r

K1 = (1/2)(Mb)v² + Ir(w1²)

= (1/2)(Mr/4)v² + (1/3)(Mr)L²(0²)

= (1/8)(Mr)v²

K2 = (1/2)(Isys)(ω2²)

I(sys) is (Ir+ Ib). This gives us;

Isys = (19L²Mr/48)

K2 =(1/2)(19L²Mr/48)(6v/19L)²

= (1/2)(36v²Mr/(48x19)) = 3v²Mr/152

Thus, the ratio, K2/K1 =

[3v²Mr/152] / (1/8)(Mr)v² = 24/152 = 3/19

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3 years ago
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katen-ka-za [31]

Answer:

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Latent heat is divided into two:

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Latent Heat of fusion: This is the heat  energy required to convert a substance from its solid form to its liquid form without change in temperature. E.g (Ice) When ice is heated, its temperature rise steadily until a certain temperature is reached when the solid begins to melts.

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From The above, Latent heat brings about  a change of state of a substance at a steady temperature.

The right option is (d) substance undergoing a change of state

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3 years ago
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