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4 years ago

How much force does it take to accelerate a 3.50 kg mass from 3.00 m/s to 17.0 m/s in a time of 2.00 seconds?

Physics

1 answer:

zheka24 [161]4 years ago

5 0

Answer:

Force = 24.5 Newton

Explanation:

Given the following data;

Mass = 3.50 kg

Initial velocity, u = 3 m/s

Final velocity, v = 17 m/s

Time, t = 2 seconds

To find the force;

First of all, we would determine the acceleration of the object using the formula;

Acceleration = (v - u)/t

Acceleration = (17 - 3)/2

Acceleration = 14/2

Acceleration = 7 m/s²

Now, we can find the force using the formula;

Force = mass * acceleration

Force = 3.5 * 7

Force = 24.5 Newton

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Thus,

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3 years ago

A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp

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So, in the current problem, the natural length of the spring is not required to find the spring constant $k$ .

$\text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}$

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