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Llana [10]
3 years ago
15

Would the sum of 5.7 cm and 6.2 cm need to be rounded? Why or why not?

Physics
1 answer:
Alekssandra [29.7K]3 years ago
7 0
No, the sum of 5.7 cm and 6.2 cm doesn't need to be rounded.

5.7 cm + 6.2 cm = 11.9 cm

Now,
Both 5.7 cm and 6.2 cm has 1 decimal place. So, their sum also has to be equal to 1 decimal place tooo. As you can see their sum also has 1 decimal place. So, you don't have to round it.
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the person is not able to see the far lying object clearly. which type of lens will the doctor prescribe him give reason?
ASHA 777 [7]

Answer:

correction of farsightedness uses a converging lenses that compensates for the under convergence by the eye. the converging lens produces an image farther from the eye than the object so that farsighted can see it clearly.

8 0
3 years ago
It is summertime and the temperature is 100 degrees Fahrenheit. Johnny decides he is going to go swimming. He jumps in his pool
Aloiza [94]

Answer:

Water temperatures are slow to heat up, It takes 4 times the energy to heat up water than to heat air. Water also "feels" colder because water is a more efficent medium than air to cool our body down.

Re word it tho

Hope this helps!!

3 0
3 years ago
Whats the measure of the force of gravity on a object
uranmaximum [27]
If it's a small object near another gigantic object, then we usually call that the small object's "weight".
8 0
3 years ago
A cubical box measuring 1.29 m on each side contains a monatomic ideal gas at a pressure of 2.0 atm How much thermal energy do t
Marrrta [24]

Answer:

a) U = 652.545\,kJ, b) v \approx 659.568\,\frac{m}{s}

Explanation:

a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

Q = U

The internal energy for a monoatomic ideal gas is:

U = \frac{3}{2} \cdot n \cdot R_{u} \cdot T

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:

T = \frac{P\cdot V}{n\cdot R_{u}}

T = \frac{(202.65\,kPa)\cdot(1.29\,m)^{3}}{(1\,kmole)\cdot(8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K} )}

T = 52.325\,K

The thermal energy contained by the gas is:

U = \frac{3}{2}\cdot (1\,kmole)\cdot (8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K})\cdot (52.325\,K)

U = 652.545\,kJ

b) The physical model for the cat is constructed from Work-Energy Theorem:

U = \frac{1}{2}\cdot m_{cat} \cdot v^{2}

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:

v = \sqrt{\frac{2 \cdot U}{m_{cat}}}

v = \sqrt{\frac{2\cdot (652.545 \times 10^{3}\,J)}{3\,kg} }

v \approx 659.568\,\frac{m}{s}

3 0
3 years ago
The time required from the passing of one crest to the next is called the wave's
Strike441 [17]
That's the wave's ' period '.
It's the reciprocal of the wave's frequency.
8 0
3 years ago
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