Answer:
(a) 3.75
(b) 2.00083
(c) 0.4898
Step-by-step explanation:
It is provided that X has a continuous uniform distribution over the interval [1.3, 6.2].
(a)
Compute the mean of X as follows:

(b)
Compute the variance of X as follows:

(c)
Compute the value of P(X < 3.7) as follows:
![P(X < 3.7)=\int\limits^{3.7}_{1.3}{\frac{1}{6.2-1.3}}\, dx\\\\=\frac{1}{4.9}\times [x]^{3.7}_{1.3}\\\\=\frac{3.7-1.3}{4.9}\\\\\approx 0.4898](https://tex.z-dn.net/?f=P%28X%20%3C%203.7%29%3D%5Cint%5Climits%5E%7B3.7%7D_%7B1.3%7D%7B%5Cfrac%7B1%7D%7B6.2-1.3%7D%7D%5C%2C%20dx%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B4.9%7D%5Ctimes%20%5Bx%5D%5E%7B3.7%7D_%7B1.3%7D%5C%5C%5C%5C%3D%5Cfrac%7B3.7-1.3%7D%7B4.9%7D%5C%5C%5C%5C%5Capprox%200.4898)
Thus, the value of P(X < 3.7) is 0.4898.
Answer:
b
Step-by-step explanation:
lucky guess
Triangle 1 area : 6×4 /2 -> 24/2 -> 12
triangle 2 area : 9×8 /2 -> 72/2 -> 36
rectangle 1 area : 6×4 -> 24
rectangle 2 area : 15×4 -> 60
12+36+24+60
48+24+60
72+60
132
Answer:
As x —> negative infinity, f(x) —> negative infinity
As x —> positive infinity, f(x) —> positive infinity.
Step-by-step explanation:

An odd-degree function, meaning that the graph starts from negative infinity at x —> negative infinity and positive infinity at x —> positive infinity.
As x —> negative infinity, f(x) —> negative infinity
As x —> positive infinity, f(x) —> positive infinity.
An odd-degree function is an one-to-one function so whenever x approaches positive, f(x) will also approach positive.
Answer:
The answer is B
Step-by-step explanation:
I got a giid grade