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umka2103 [35]
2 years ago
10

How many million bacteria were in the dish at 9 a.mt

Mathematics
1 answer:
TEA [102]2 years ago
3 0

Answer:it depends what was on it but i would say about 500

Step-by-step explanation:

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Which of the lists of letters all have line symmetry?
Sunny_sXe [5.5K]

Answer:

The first row

Step-by-step explanation:

Letters A,B,C,D

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2 years ago
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What is the value of y in the solution to this system of equations?<br> y=3-2x/2<br> 4x-6y=36
Paul [167]

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3 years ago
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Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
2 years ago
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Solve the equation and check your solution. (If all real numbers are solutions, enter REALS. If there is no solution, enter NO S
shepuryov [24]

Answer:

y=6/5 or 1 1/5

Step-by-step explanation:

combine like terms

5y+1= 10y-5

subtract 5y from both sides

1=5y-5

add 5 to both sides

6=5y

divide by 5 on both sides

6/5=y

5 0
3 years ago
In the expression 2x + 8y -4 ,what is the constant
olasank [31]

Answer: The constant is -4 cause it will never change from x or y value.


Step-by-step explanation:


6 0
2 years ago
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