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Georgia [21]
3 years ago
11

−t/4=−3π What is the answer to T

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
7 0
I think the answer is 4+3(pie)= t
You might be interested in
For a cube whole side lenght is 4 in , the expression 4 to the 3 could represent
S_A_V [24]

Answer:

Step-by-step explanation:

The volume of a cube.

The formula is V = s^3 where is the the "whole side length" of the cube. The cube requires three dimensions be multiplied together to find its volume.

That's why the formula is written as V = s^3. It means that V = s * s * s which is three sides multiplied together. They also need to be at right angles to each other.

4 0
3 years ago
I need to solve all answers
yan [13]

Answer:

Answers for 19, 20, 22, 24, and 25.

Step-by-step explanation:

19. 23x - 16 + 8x - 21 = 180  

    x = 7

    23 (7) - 16 = 7y - 23

    y = 24

20. 10x -17 = 8x + 1

     x = 9

    6y + 29 + 73 = 180

    y = 13

22. 8x - 35 + 6x - 5 + 3x - 1 = 180

      x = 13

24. m<R is 74

     m<Q is 32

25. m<E is 37

     m<G is 37

I didn't know the answers for all, but I hope this helps in some way!

8 0
2 years ago
4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.
nikitadnepr [17]

Answer:

\sum_{n=0}^9cos(\frac{\pi n}{2})=1

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}

Step-by-step explanation:

\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))

=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})

=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1

2nd

\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}

=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0

3th

\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))

=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}

What we use?

We use that

e^{i\pi n}=cos(\pi n)+i sin(\pi n)

and

\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}

6 0
4 years ago
Please help I need it!?
Amiraneli [1.4K]
What do you need help with
5 0
3 years ago
Can anyone help? I’ll give brainly if answer is correct!
ICE Princess25 [194]
12 centimeters i believe
7 0
3 years ago
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