Answer:
we have the equation y = (1/2)*x + 4.
now, any equation that passes through the point (4, 6) will intersect this line, so if we have an equation f(x), we must see if:
f(4) = 6.
if f(4) = 6, then f(x) intersects the equation y = (1/2)*x + 4 in the point (4, 6).
If we want to construct f(x), an easy example can be:
f(x) = y = k*x.
such that:
6 = k*4
k = 6/4 = 3/2.
then the function
f(x) = y= (3/2)*x intersects the equation y = (1/2)*x + 4 in the point (4, 6)
Answer:
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Answer:
Step-by-step explanation:
a) The relative minimum of the function from the graph is -18 at x=0.
b) The graph ends with two arrows which means it continues from there indefinitely. So the function increases from x equal to negative infinity to -2 and then from 0 to +2.
Answer:
Step-by-step explanation:
<u>Equation Solving</u>
We are given the equation:
![\displaystyle x=\sqrt[3]{\frac{3y+16}{2y+9}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D)
i)
To make y as a subject, we need to isolate y, that is, leaving it alone in the left side of the equation, and an expression with no y's to the right side.
We have to make it in steps like follows.
Cube both sides:
![\displaystyle x^3=\left(\sqrt[3]{\frac{3y+16}{2y+9}}\right)^3](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E3%3D%5Cleft%28%5Csqrt%5B3%5D%7B%5Cfrac%7B3y%2B16%7D%7B2y%2B9%7D%7D%5Cright%29%5E3)
Simplify the radical with the cube:
Multiply by 2y+9
Simplify:
Operate the parentheses:
Subtract 3y and 
:
Factor y out of the left side:
Divide by 
:
ii) To find y when x=2, substitute:
Answer:
=1y -2z
Step-by-step explanation:
