Slope = 0 do answer is y = 1
Answer:
The answer to your question is below
Step-by-step explanation:
5) 2x² -7x + 34
x + 5 2x³ + 3x² - x + 1
-2x³ -10x²
0 - 7x² - x
+7x² +35x
0 +34x + 1
-34x - 170
0 - 160
Quotient = 2x² - 7x + 34
Remainder = -160
6) 2x² - 3x + 1
3x + 1 6x³ - 7x² + 0x + 2
-6x³ -2x²
0 -9x² + 0x
+9x² +3x
0 +3x + 2
- 3x - 1
0 + 1
Quotient = 2x² - 3x + 1
Remainder = 1
Answer:
The solution of system of equation is (-2,0)
Step-by-step explanation:
Given system of equation are
Equation 1 : 2x+y=(-4)
Equation 2 : y+
x=(-1)
To plot the equation of line, we need at least two points
For Equation 1 : 2x+y=(-4)
Let x=0
2x+y=(-4)
2(0)+y=(-4)
y=(-4)
Let x=1
2x+y=(-4)
2(1)+y=(-4)
y=(-6)
Therefore,
The required points for equation is (0,-4) and (1,-6)
For Equation 2 : y+
x=(-1)
Let x=0
y+
x=(-1)
y+
(0)=(-1)
y=(-1)
Let x=2
y+
x=(-1)
y+
(2)=(-1)
y=(-2)
The required points for equation is (0,-1) and (2,-2)
Now, plot the graph using this points
From the graph,
The red line is equation 1 and blue line is equation 2
Since. The point of intersection is solution of system of equations
The solution of system of equation is (-2,0)
Answer:
all i see is ..........
Step-by-step explanation: